Question

当应用未运行且用户按下通知时收到推送通知时，它会消失并且日志显示：

2019-10-22 12:42:45.747 23260-23260/de.app.test.staging E/FirebaseMessaging: Notification pending intent canceled

以下是应该作为启动器活动启动的SplashActivity：

    <activity
        android:name="de.app.test.login.SplashActivity"
        android:screenOrientation="portrait"
        android:exported="true"
        android:theme="@style/Theme.AppCompat.Light.NoActionBar.FullScreen">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

这里有什么问题？

Answer 1

Forground应用程序：

您需要PendingIntent才能打开应用。

尝试一下：

NotificationManager notificationManager = (NotificationManager) context
        .getSystemService(Context.NOTIFICATION_SERVICE);
Notification notification = new Notification(icon, message, when);

Intent notificationIntent = new Intent(context, SplashActivity.class);

notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP
        | Intent.FLAG_ACTIVITY_SINGLE_TOP);

PendingIntent intent = PendingIntent.getActivity(context, 0,
        notificationIntent, 0);

notification.setLatestEventInfo(context, title, message, intent);
notification.flags |= Notification.FLAG_AUTO_CANCEL;
notificationManager.notify(0, notification);

如果“活动”处于后台或关闭状态，则通知消息将显示在通知中心中，以指示应用启动器活动。

您可以使用BroadcastReceiver类。当您关闭应用程序时，广播可以收听此操作。因此，如果您创建一个BroadcastReceiver类，就不会遇到这个问题。

public class ClosedBroadcastReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(Context context, Intent intent) {

        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
            context.startForegroundService(new Intent(context, HomePage.class));
        } else {
            context.startService(new Intent(context, HomePage.class));
        }
    }
}

更多信息：

https://firebase.google.com/docs/cloud-messaging/android/receive

Answer 2

您需要在notificationBuilder实例中设置未决对象

 mBuilder = new NotificationCompat.Builder(this, CHANNEL_ID);
    Intent intent = new Intent(context, TargetActivity.class));
    PendingIntent pendingIntent = PendingIntent.getActivity(this, 0, intent, 0);
    builder.setContentIntent(pendingIntent);

请注意，CHANNEL_ID用于大于或等于Oreo的内部版本

   if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
        CHANNEL_ID = createNotificationChannel(CHANNEL_ID, "channelName");
    }


  @RequiresApi(Build.VERSION_CODES.O)
private String createNotificationChannel(String channelId, String channelName) {
    // Create the NotificationChannel, but only on API 26+ because
    // the NotificationChannel class is new and not in the support library

    String description = "description";

    NotificationChannel channel = new NotificationChannel(channelId, channelName, NotificationManager.IMPORTANCE_NONE);
    channel.setLightColor(Color.BLUE);
    channel.setLockscreenVisibility(Notification.VISIBILITY_PRIVATE);
    channel.setDescription(description);
    // Register the channel with the system; you can't change the importance
    // or other notification behaviors after this
    mNotificationManager.createNotificationChannel(channel);
    return channelId;

}

Answer 3

对于任何寻求答案的人，后端都将“ click_action”发送给通知，因此该活动没有意图过滤器。

对我来说，click_action是“ OPEN_ACTIVITY_1”，因此我向SplashActivity添加了一个意图过滤器，如下所示：

<intent-filter>
        <action android:name="OPEN_ACTIVITY_1" />
        <category android:name="android.intent.category.DEFAULT" />
</intent-filter>

点击通知无法启动该应用

3 个答案: