Question

我想将JSON数据插入sql服务器表中，我通过URL检索json数据，并且通过明显的错误{"Must declare the scalar variable \"@Name\"."}在按钮click事件中写入了插入逻辑，因为我不提供任何用于插入数据的参数，因为我无法通过硬编码来传递这些参数

private string HttpContent(string url)
        {
            WebRequest objRequest = System.Net.HttpWebRequest.Create(url);
            StreamReader sr = new StreamReader(objRequest.GetResponse().GetResponseStream());
            string result = sr.ReadToEnd();
            sr.Close();
            return result;
        }
        protected void btnsave_Click(object sender, EventArgs e)
        {
            var conString = ConfigurationManager.ConnectionStrings["SQLDBConnection"];
            string strConnString = conString.ConnectionString;
            SqlConnection conn = new SqlConnection(strConnString);
            SqlCommand com;
            string data = HttpContent(txturl.Text);
                JavaScriptSerializer jsSerializer = new JavaScriptSerializer();
                var table = jsSerializer.Deserialize<dynamic>(data);
                conn.Open();
                com = new SqlCommand("INSERT INTO tbl_insert_json (Name, Mobile, Email) VALUES(@Name, @Mobile, @Email)", conn);
                com.CommandType = CommandType.Text;
                int refId = com.ExecuteNonQuery();
                conn.Close();
                if (refId > 0)
                {
                    Response.Write("{\"response\":{\"status\":\"success\",\"msg\":\"Details Saved Successfully..\"}}");
                }
                else
                {
                    Response.Write("{\"response\":{\"status\":\"fail\",\"msg\":\"oops!! something went wrong\"}}");
                }
            }

现在我的问题是我应该更改什么或如何将数据插入sql server表

我在每个循环中使用它来映射每一行，然后插入但对我不起作用请分享任何想法或方法将数据插入表中？我在com = new SqlCommand("INSERT INTO tbl_insert_json (Name, Mobile, Email) VALUES(@Name, @Mobile, @Email)", conn);本节中遇到问题，如何将这些参数插入表中

Answer 1

必须在SqlCommand对象的实例行之后添加参数以用json值替换参数，例如：

    com = new SqlCommand("INSERT INTO tbl_insert_json (Name, Mobile, Email) VALUES(@Name, @Mobile, @Email)", conn);
    com.Parameters.Add("@Name", SqlDbType.NChar);
    com.Parameters["@Name"].Value = "NameDataJson";

    com.Parameters.Add("@Mobile", SqlDbType.NChar);
    com.Parameters["@Mobile"].Value = "MobileDataJson";

    com.Parameters.Add("@Email", SqlDbType.NChar);
    com.Parameters["@Email"].Value = "EmailDataJson";

将动态JSON数据插入数据库

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