Question

我编写了以下SQL查询：

SELECT DISTINCT i.IncidentReference Reference, s.Name Site, it.Description IncidentTypes
    , i.Description, FORMAT(i.CreatedOn,'d MMM yyyy', 'en-US' ) Logged 
FROM Incident i 
INNER JOIN TEST_USWM_TestAutomation.TEST_USWM.uvw_AvailaibleSites s ON i.SiteId = s.Id 
JOIN IncidentIncidentType iit ON i.Id = iit.IncidentId 
JOIN IncidentType it ON iit.IncidentTypeId = it.Id 
JOIN IncidentStatus ins ON i.IncidentStatusId = ins.Id 
WHERE s.Id = 1 /*:siteId */
AND ins.Name = 'Logged' 
AND i.CreatedOn BETWEEN DATEADD(DAY, -30, GETUTCDATE()) AND GETUTCDATE()

哪个返回以下结果：

Reference  Site  IncidentTypes                 Description    Logged
7032       0110  Refrigeration Outage          njfdgdf        25 Sep 2019
7095       0110  Fire/False Evacuation         testing        2 Oct 2019
7096       0110  Fire/False Evacuation         testing        2 Oct 2019
7097       0110  Fire/False Evacuation         test           2 Oct 2019
7097       0110  Flood                         test           2 Oct 2019
7097       0110  Gas Leak/Suspected Gas Leak   test           2 Oct 2019
7098       0110  Flood                         testing        2 Oct 2019
7168       0110  Fire/False Evacuation         test           7 Oct 2019
7330       0110  Refrigeration Outage          Test           15 Oct 2019

但是，我希望将具有相同引用的所有行合并为一行。因此，例如，对于参考-7097，我希望看到IncidentTypes列看起来像-气体泄漏/可疑气体泄漏，火灾/虚假疏散，洪水。

什么是最好的方法？

编辑：我已经尝试了@GMB在下面发布的查询，但遇到了错误-函数'STRING_AGG'可能没有WITHIN GROUP子句。这似乎与我使用的SQL Server版本有关。是否有另一种方法可以解决此问题而无需升级版本？

编辑：@Gordon Linoff查询的输出-

Answer 1

在MySql中，您可以使用group_concat（it.Description），然后按引用进行分组

SELECT DISTINCT i.IncidentReference Reference, s.Name Site, group_concat(it.Description) IncidentTypes, 
i.Description, FORMAT(i.CreatedOn,'d MMM yyyy', 'en-US' ) Logged 
FROM Incident i 
INNER JOIN TEST_USWM_TestAutomation.TEST_USWM.uvw_AvailaibleSites s ON i.SiteId = s.Id 
JOIN IncidentIncidentType iit ON i.Id = iit.IncidentId 
JOIN IncidentType it ON iit.IncidentTypeId = it.Id 
JOIN IncidentStatus ins ON i.IncidentStatusId = ins.Id 
WHERE s.Id = 1 /*:siteId */
AND ins.Name = 'Logged' 
AND i.CreatedOn BETWEEN DATEADD(DAY, -30, GETUTCDATE()) AND GETUTCDATE() Group by reference;

Answer 2

在旧版SQL Server中，您可以使用：

SELECT i.IncidentReference as Reference, 
       s.Name as Site, 
       STUFF( (SELECT it.Description + ','
               FROM IncidentType it
               WHERE iit.IncidentTypeId = it.Id 
               ORDER BY it.Description
               FOR XML PATH ('')
              ), 1, 2, ''
             ) as IncidentTypes,
      i.Description,
      FORMAT(i.CreatedOn,'d MMM yyyy', 'en-US' ) as Logged 
FROM Incident i JOIN
     TEST_USWM_TestAutomation.TEST_USWM.uvw_AvailaibleSites s 
     ON i.SiteId = s.Id JOIN
     IncidentStatus ins
     ON i.IncidentStatusId = ins.Id 
WHERE s.Id = 1 /*:siteId */ AND
      ins.Name = 'Logged' AND
      i.CreatedOn BETWEEN DATEADD(DAY, -30, GETUTCDATE()) AND GETUTCDATE();

我认为不需要外部GROUP BY。

Answer 3

您需要使用聚合。

使用GETUTCDATE()往往表明您正在使用SQL Server。在此RDBMS中，可以使用函数STRING_AGG()来汇总描述，如下所示：

SELECT 
    i.IncidentReference Reference, 
    s.Name Site, 
    STRING_AGG(i.Description, ',') WITHIN GROUP(ORDER BY i.Description) IncidentTypes,
    i.Description,
    FORMAT(i.CreatedOn,'d MMM yyyy', 'en-US' ) Logged 
FROM 
    Incident i 
    JOIN TEST_USWM_TestAutomation.TEST_USWM.uvw_AvailaibleSites s ON i.SiteId = s.Id 
    JOIN IncidentIncidentType iit ON i.Id = iit.IncidentId 
    JOIN IncidentType it ON iit.IncidentTypeId = it.Id 
    JOIN IncidentStatus ins ON i.IncidentStatusId = ins.Id 
WHERE 
    s.Id = 1 /*:siteId */
    AND ins.Name = 'Logged' 
    AND i.CreatedOn BETWEEN DATEADD(DAY, -30, GETUTCDATE()) AND GETUTCDATE()
GROUP BY
    i.IncidentReference Reference, 
    s.Name Site, 
    i.Description,
    FORMAT(i.CreatedOn,'d MMM yyyy', 'en-US' ) Logged

将数据库中的多列合并为一列？

3 个答案: