Question

我想创建一个面积计算器，因为我有一些空闲时间，所以我尝试先在终端上运行它，并且它可以正常工作，但是当我决定添加一个精巧的GUI时，出现了一个错误我的代码是这个

from tkinter import *
screen = Tk()
screen.title("Area of Circle Calculator")
screen.geometry("500x500")
def submit():
    global done
    pi = 3.14159265359
    an = int(pi * radius*radius)
    laod = Label(screen, text = "Hello" % (an))
    load.grid()
ask = Label(screen, text = "What is the radius of the circle?")
ask.pack()
radius = Entry(screen)
radius.pack()
done = Button(screen, text="submit", command = submit)
done.pack()
screen.mainloop()

这是我得到的错误

C:\Users\Timothy\Desktop>python aoc.py
Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Users\Timothy\AppData\Local\Programs\Python\Python37-32\lib\tkinter\_
_init__.py", line 1705, in __call__
    return self.func(*args)
  File "aoc.py", line 8, in submit
    an = int(pi * radius*radius)
TypeError: unsupported operand type(s) for *: 'float' and 'Entry'

C:\Users\Timothy\Desktop>

我尝试将int（）添加到条目中，但这确实有用

Answer 1

您需要调用radius.get()来获取Entry小部件的当前值。这里是一些documentation。

您的代码中还有其他错误和错别字，因此我将其修复并使其更符合PEP 8 - Style Guide for Python Code。

结果如下：

from math import pi
from tkinter import *


screen = Tk()
screen.title("Area of Circle Calculator")
screen.geometry("500x500")

def submit():
    r = float(radius.get())
    an = pi * r**2
    load = Label(screen, text="Hello %f" % (an))
    load.pack()

ask = Label(screen, text="What is the radius of the circle?")
ask.pack()

radius = Entry(screen)
radius.pack()

done = Button(screen, text="submit", command=submit)
done.pack()

screen.mainloop()

如何在Tkinter中输入int

1 个答案: