Question

我的上传文件中有此错误。语法是正确的，问题出在哪里？

错误：

is_uploaded_file（）期望参数1为字符串，数组在第34行的C：\ Program Files \ EasyPHP-5.3.5.0 \ www \ bena_website \ admin \ variables \ upload_img.php中给出

<h3>Please Choose a File and click Submit</h3>

        <form enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
            <input type="hidden" name="MAX_FILE_SIZE" value="10000000" />
            <input name="userfile[]" type="file" />
            <input type="submit" value="Submit" />
        </form>

<?php
        // check if a file was submitted
        if(!isset($_FILES['userfile'])) {
            echo '<p>Please select a file</p>';
        }
        else
            {
            print_r( $_FILES );
            try {
                upload();
                // give praise and thanks to the php gods
                echo '<p>Thank you for submitting</p>';
            }
            catch(Exception $e) {
                echo $e->getMessage();
                echo 'Sorry, could not upload file';
            }
        }
// the upload function
function upload(){

if(is_uploaded_file($_FILES['userfile']['tmp_name'])) {

    // check the file is less than the maximum file size
    if($_FILES['userfile']['size'] < $maxsize)
        {
    // prepare the image for insertion
    $imgData =addslashes (file_get_contents($_FILES['userfile']['tmp_name']));
    // $imgData = addslashes($_FILES['userfile']);

    // get the image info..
      $size = getimagesize($_FILES['userfile']['tmp_name']);

    // put the image in the db...
      // database connection
      mysql_connect("localhost", "root", "") OR DIE (mysql_error());

      // select the db
      mysql_select_db ("bena") OR DIE ("Unable to select db".mysql_error());

    // our sql query
    $sql = "INSERT INTO testblob
            ( image_id , image_type ,image, image_size, image_name)
            VALUES
            ('', '{$size['mime']}', '{$imgData}', '{$size[3]}', '{$_FILES['userfile']['name']}')";

    // insert the image
    if(!mysql_query($sql)) {
        echo 'Unable to upload file';
        }
    }
}
else {
     // if the file is not less than the maximum allowed, print an error
     echo
      '<div>File exceeds the Maximum File limit</div>
      <div>Maximum File limit is '.$maxsize.'</div>
      <div>File '.$_FILES['userfile']['name'].' is '.$_FILES['userfile']['size'].' bytes</div>
      <hr />';
     }
}
?>

Answer 1

在upload（）函数的开头发出要学习的$ _FILES数组的结构，结构内部是什么：

print_r( $_FILES );

如其中一条评论中所述，如果你有一个像

这样的表格

<form ... method="post" enctype="multipart/form-data">
   <input type="file" name="userfile[0]" />
   <input type="file" name="userfile[1]" />
   ...
</form>

或

<form ... method="post" enctype="multipart/form-data">>
   <input type="file" name="userfile[]" />
   <input type="file" name="userfile[]" />
   ...
</form>

您需要访问此

$_FILES[ 'userfile' ][ 'tmp_name' ]

就像一个数组：

$_FILES['userfile'][ 'tmp_name' ][ 0 ]
$_FILES['userfile'][ 'tmp_name' ][ 1 ]

Answer 2

您还可以查看$_FILES['userfile']['error']是否与零不同。例如，如果它是2，则文件大小大于HTML中设置的大小。有关错误消息的更多信息，请选中http://php.net/manual/en/features.file-upload.errors.php

is_uploaded_file数组给出错误

2 个答案: