我正在使用.netcore 3.0构建通用数据存储库。使用EF Core。我该如何在不需要提供实际实体名称的地方设置服务,例如:
services.AddScoped<RepositoryBase<Feature>>();
有没有一种方法可以配置所有这些选项?
这些主要是CRUD操作。
通用存储库
namespace CoreAPI1.Data.Services
{
public class RepositoryBase<TEntity> where TEntity : class
{
private readonly DbContext _context;
private readonly DbSet<TEntity> _dbSet;
public RepositoryBase(DbContext context)
{
_context = context;
if (_context == null)
throw new ArgumentNullException();
_dbSet = context.Set<TEntity>();
}
public async Task<IEnumerable<TEntity>> GetAll()
{
return _dbSet.AsNoTracking().ToList();
}
}
}
服务
public static void ConfigureServices(IServiceCollection services)
{
services.AddDbContext<TruckContext>(ServiceLifetime.Scoped);
services.AddScoped<IFileService, FileService>();
services.AddScoped<IImageRepository, ImageRepository>();
services.AddScoped<RepositoryBase<Feature>>();
services.AddControllers();
// services.AddAutoMapper(typeof(Truck));
services.AddMvc(_x=>_x.EnableEndpointRouting =
false).SetCompatibilityVersion(CompatibilityVersion.Version_3_0);
}
呼叫控制者
namespace CoreAPI1.Data.Controllers
{
[Route("api/features")]
[ApiController]
public class FeaturesController :ControllerBase
{
private RepositoryBase<Data.Entities.Feature> _repository;
private IMapper _mapper;
public FeaturesController(RepositoryBase<Data.Entities.Feature> repository, IMapper mapper)
{
_repository = repository ?? throw new ArgumentNullException(nameof(_repository));
_mapper = mapper ?? throw new ArgumentNullException(nameof(mapper));
}
[HttpGet]
public async Task<IEnumerable<Domain.Models.Feature>> GetFeatures()
{
var _features = await _repository.GetAllAsync();
List<Domain.Models.Feature> _returnedFeatures = new List<Domain.Models.Feature>();
try
{
foreach (var f in _features)
{
var _returnedFeature = _mapper.Map<Domain.Models.Feature>(f);
_returnedFeatures.Add(_returnedFeature);
}
return _returnedFeatures;
}
catch (Exception ex)
{
throw new Exception(ex.ToString());
}
}
}
}
答案 0 :(得分:2)
如果您要谈论的是,则可以通用地注册类型:
services.AddScoped(typeof(IRepository<>), typeof(Repository<>));
例如,这将为Repository<Foo>
注入IRespository<Foo>
。
答案 1 :(得分:0)
包装DbContext并创建存储库的实现工作单元类。