将对象推送到值等于的对象数组

Question

我有一系列看起来像的对象：

我想基于site_nm添加对象。我希望能够使这个对象数组均匀。我想通过增加日期为每个site_nm添加相等数量的对象。所以我在做：

let data = [{
  "site_nm": "gs Universe",
  "date": "2019-10-01",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "gs Gameplay",
  "date": "2019-10-01",
  "sigh": 4,
  "yo": 3,
  "wokay": 2
}, {
  "site_nm": "gs Universe Trailers",
  "date": "2019-10-01",
  "sigh": 5,
  "yo": 5,
  "wokay": 0
}, {
  "site_nm": "TR",
  "date": "2019-10-01",
  "sigh": 4,
  "yo": 4,
  "wokay": 0
}, {
  "site_nm": "gs",
  "date": "2019-10-01",
  "sigh": 5,
  "yo": 5,
  "wokay": 2
}, {
  "site_nm": "GB",
  "date": "2019-10-01",
  "sigh": 1,
  "yo": 1,
  "wokay": 1
}, {
  "site_nm": "cn",
  "date": "2019-10-01",
  "sigh": 4,
  "yo": 4,
  "wokay": 1
}, {
  "site_nm": "Roadshow",
  "date": "2019-10-01",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "TV",
  "date": "2019-10-01",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "ZD",
  "date": "2019-10-01",
  "sigh": 2,
  "yo": 2,
  "wokay": 0
}, {
  "site_nm": "Carfection",
  "date": "2019-10-01",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "gs Trailers",
  "date": "2019-10-01",
  "sigh": 3,
  "yo": 3,
  "wokay": 0
}, {
  "site_nm": "gs News",
  "date": "2019-10-01",
  "sigh": 3,
  "yo": 3,
  "wokay": 0
}, {
  "site_nm": "gs Mobile",
  "date": "2019-10-01",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "gs Universe Trailers",
  "date": "2019-10-02",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "gs Gameplay",
  "date": "2019-10-04",
  "sigh": 6,
  "yo": 6,
  "wokay": 2
}, {
  "site_nm": "Roadshow",
  "date": "2019-10-02",
  "sigh": 2,
  "yo": 2,
  "wokay": 0
}, {
  "site_nm": "gs",
  "date": "2019-10-02",
  "sigh": 3,
  "yo": 3,
  "wokay": 2
}, {
  "site_nm": "TR",
  "date": "2019-10-02",
  "sigh": 4,
  "yo": 3,
  "wokay": 0
}, {
  "site_nm": "cn Highlights",
  "date": "2019-10-03",
  "sigh": 8,
  "yo": 8,
  "wokay": 0
}, {
  "site_nm": "gs Universe",
  "date": "2019-10-02",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "cn en Espa\u00f1ol",
  "date": "2019-10-02",
  "sigh": 6,
  "yo": 6,
  "wokay": 0
}, {
  "site_nm": "gs Trailers",
  "date": "2019-10-02",
  "sigh": 2,
  "yo": 2,
  "wokay": 0
}, {
  "site_nm": "ZD",
  "date": "2019-10-02",
  "sigh": 4,
  "yo": 4,
  "wokay": 1
}, {
  "site_nm": "cn",
  "date": "2019-10-05",
  "sigh": 5,
  "yo": 5,
  "wokay": 1
}, {
  "site_nm": "TV",
  "date": "2019-10-02",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "CH",
  "date": "2019-10-02",
  "sigh": 1,
  "yo": 1,
  "wokay": 0
}, {
  "site_nm": "GB",
  "date": "2019-10-02",
  "sigh": 3,
  "yo": 3,
  "wokay": 3
}, {
  "site_nm": "DLNow",
  "date": "2019-10-02",
  "sigh": 1,
  "yo": 0,
  "wokay": 0
}, {
  "site_nm": "gs News",
  "date": "2019-10-02",
  "sigh": 2,
  "yo": 2,
  "wokay": 0
}];
//sort by site_nm
function compare(a, b) {
  const site_a = a.site_nm.toUpperCase();
  const site_b = b.site_nm.toUpperCase();
  let comparison = 0;
  if (site_a > site_b) {
    comparison = 1;
  } else if (site_a < site_b) {
    comparison = -1;
  }
  return comparison;
}
json = data.sort(compare);
console.log(json.length);
let sites = [...new Set(json.map(({
  site_nm
}) => site_nm))].sort();
let dates = [...new Set(json.map(({
  date
}) => date))].sort();
for (var date = moment(dates[0], "YYYY-MM-DD"); date <= moment(dates[dates.length - 1], "YYYY-MM-DD"); date = date.add(1, 'days')) {
  // console.log(date);
  var dateFormatted = date.format("YYYY-MM-DD");
  console.log(dateFormatted);
  function iterate(item) {
    if (!dates.includes(dateFormatted)) {
      json.push({
        "site_nm": item,
        "date": dateFormatted,
        "sigh": "",
        "yo": "",
        "wokay": ""
      });
    }
  }
}
sites.forEach(iterate);
console.log(json.length);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/moment.min.js"></script>

它增加了我的日期，但是我无法通过site_nm添加它。对于每个网站，我要在对象中添加缺少的日期。我总共有18个不同的站点，总共有5天，所以我希望JSON的总长度为18 * 5 = 90。每个站点5个对象。如何为每个站点进行forEach？