假设有两个列名称SrNo和Salary,我需要第三列,其结果将显示如下:-
import unittest
from urlunshort3 import UrlUnshortener
from urllib.request import Request, urlopen
import urllib.request
def download_file2(download_url):
print(download_url)
url = download_url
response = urllib.request.urlopen(url)
data = response.read()
with open('C:/Users/usuario/Desktop/files/example.pdf', 'wb') as archivo:
archivo.write(data)
with open('C:/Users/usuario/Desktop/files/example.pdf', 'r') as archivo:
print("True")
download_file2(UrlUnshortener().resolve_short("http://bit" + ".ly/31wMeIN"))
因此它将通过将先前的列值添加到当前值来增加,并且应该仅使用select语句而不对其进行任何循环。
答案 0 :(得分:3)
您正在寻找累计金额。
最简单的方法是:
select t.*, sum(salary) over (order by srno) as running_salary
from t;
使用order by
时不需要窗口框架。
答案 1 :(得分:2)
使用新数据集,您可以使用窗口函数和ROWS BETWEEN
:
SELECT SrNo,
Salary,
SUM(Salary) OVER (ORDER BY SrNo
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Result
FROM YourTable;