Question

我正在尝试根据日期过滤数组。

var items = [
 {
   createdBy: "suriyan"
   product: "tv"
   from: "2019-10-15T18:30:00.000Z"
   to: "2019-10-29T18:30:00.000Z"
 },
 {
  createdBy: "suriyan"
  product: "phone"
  from: "2019-10-19T18:30:00.000Z"
  to: "2019-10-29T18:30:00.000Z"
 }
]

filtered:[];

for(let i=0;i<this.items.length;i++){
  const now = new Date();
  if(now>this.items[i].from){
    this.filtered.push(this.items[i])
  }
}
console.log(this.filtered);

但这对我不起作用。有人可以帮我吗预先感谢

Answer 1

您正在将Date与一个String值进行比较，因此首先将其转换为Date然后进行比较：

if(now > new Date(this.items[i].from){
    this.filtered.push(this.items[i])
}

使用RxJS，您无需循环，因此也请尝试以下操作：

var items = [{
           createdBy: "suriyan",
           product: "tv",
           from: "2019-10-15T18:30:00.000Z",
           to: "2019-10-29T18:30:00.000Z",
        },
        {
          createdBy: "suriyan",
          product: "phone",
          from: "2019-10-21T18:30:00.000Z",
          to: "2019-10-29T18:30:00.000Z",
        }
    ]
    
filtered = [];
const now = new Date();
this.filtered = items.filter(item => now > new Date(item.from));
console.log(this.filtered);

Answer 2

尝试一下。您可以直接使用Array.filter()。将new Date()转换为ISO

var items = [{
    createdBy: "suriyan",
    product: "tv",
    from: "2019-10-15T18:30:00.000Z",
    to: "2019-10-29T18:30:00.000Z",
  },
  {
    createdBy: "suriyan",
    product: "phone",
    from: "2019-10-19T18:30:00.000Z",
    to: "2019-10-29T18:30:00.000Z",
  }
]

let data = items.filter(ele => ele.from > new Date().toISOString());
console.log(data)
console.log(new Date().toISOString())// current date time

Answer 3

var items = [{
    createdBy: "suriyan",
    product: "tv",
    from: "2019-10-15T18:30:00.000Z",
    to: "2019-10-29T18:30:00.000Z",
  },
  {
    createdBy: "suriyan",
    product: "phone",
    from: "2019-10-19T18:30:00.000Z",
    to: "2019-10-29T18:30:00.000Z",
  }
]

let data = items.filter(ele => new Date().toISOString() > ele.from);
console.log(data)

Answer 4

一心一意

 const items = [
        {
            createdBy: 'suriyan',
            product: 'tv',
            from: '2019-11-15T18:30:00.000Z',
            to: '2019-11-29T18:30:00.000Z',
        },
        {
            createdBy: 'suriyan',
            product: 'phone',
            from: '2019-10-19T18:30:00.000Z',
            to: '2019-10-29T18:30:00.000Z'
        }
    ];

    items.sort((a, b) => {
        // Turn your strings into dates, and then subtract them
        // to get a value that is either negative, positive, or zero.
        return new Date(b.from) - new Date(a.from);
    });

    console.log(items);

根据日期以角度过滤数组中的数据

4 个答案: