Question

我有一个页面，显示所有用户发布的评论。在这里，我需要在当前登录用户发布的评论一侧显示删除链接，他也应该能够删除该评论（如Facebook，Orkut或任何Blogging网站）。我尝试过的示例代码是：

<?php
$user_id = 1;
$con = mysql_connect("localhost","root","root");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("blog", $con);

$result = mysql_query("SELECT * FROM replies");

while($row = mysql_fetch_array($result))
  {
  $replies = $row;
  if($replies['poster_id' == $user_id]){
      $delete = '<a href="#">Delete</a>';
  }

  echo $replies['poster_id']?></a>&nbsp;¦&nbsp;<?php echo $replies['reply_text']?>&nbsp;¦&nbsp;  <?php echo $delete?></div>

  <?php echo "<br />";
  }

mysql_close($con);
?>

这里我给出了这里硬编码的user_id。我得到的是，删除链接显示在所有评论上。我需要显示user_id的删除链接，仅显示“1”。任何人都可以建议我得到解决方案......在此先感谢...

Answer 1

<?php
if (isset($_GET['reply'],$_GET['where']))
 $result=mysql_query("Delete FROM $replies WHERE entry_id = '$_GET['reply']'");

$username = $session->username;

$result=mysql_query("SELECT * FROM $replies WHERE entry_id = '$id' ORDER by reply_id DESC");

while ($i = mysql_fetch_array($result))
{
$replies = $i;
if ($replies['poster_id'] == $username){
$delete = '<a href="delete?where='.$id.'&reply='.$replies['reply_id'].'">Delete</a>';
}
?>
<div>
<div><a href="profiles/<?php echo $replies['poster_id']?>">
<?php echo     $replies['poster_id']?></a>&nbsp;¦&nbsp;<?php echo     $replies['post_time']?>&nbsp;¦&nbsp;<?php echo $delete?></div>

<div><?php echo $replies['reply_text']?></div>

</div><br/><br/>

<?
}

Answer 2

我知道这有点老了，可能已经很好地照顾了，但是你忘记了;在$ delete之后

<?php echo $delete?>

应该是

<?php echo $delete; ?>

仅显示由PHP登录的用户发布的评论的删除链接

2 个答案: