Sequelize-TypeError:无法读取未定义的属性“ define”

时间:2019-10-19 02:29:21

标签: javascript node.js sequelize.js

编辑:我的示例中未包含代码行,该行已添加并带有注释。

我正在为新项目设置服务器,并尝试自v5以来首次使用Sequelize。在运行服务器后,将引发此错误。

/Users/me/dev/projects/my-project/node_modules/sequelize/lib/model.js:730
    options = Utils.merge(_.cloneDeep(globalOptions.define), options);
                                                    ^

TypeError: Cannot read property 'define' of undefined
    at Function.init (/Users/me/dev/projects/my-project/node_modules/sequelize/lib/model.js:730:53)
    at Object.<anonymous> (/Users/me/dev/projects/my-project/src/server/db/models/user.js:16:6)
    at Module._compile (internal/modules/cjs/loader.js:736:30)
    at Object.Module._extensions..js (internal/modules/cjs/loader.js:747:10)
    ...

在调用模型定义初始化期间发生错误:

const sequelize = require("../_db");

...

console.log('this runs');

class User extends Sequelize.Model {} // edit: this line was here
User.init(
  {
    avatar: {
      default: {
        type: Sequelize.URL,
        value: defaultAvatar
      },
      type: Sequelize.STRING
    },
    email: {
      allowNull: false,
      type: Sequelize.STRING,
      unique: true
    },
    id: {
      defaultValue: Sequelize.UUIDV1,
      primaryKey: true,
      type: Sequelize.UUID
    },
    name: {
      type: Sequelize.STRING
    },
    password: {
      allowNull: false,
      get() {
        return () => this.getDataValue("password");
      },
      type: Sequelize.STRING
    },
    salt: {
      get() {
        return () => this.getDataValue("salt");
      },
      type: Sequelize.STRING
    }
  },
  { sequelize, modelName: "user" }
);

console.log('this doesn't);

对我来说这很神秘,我不确定什么地方出了错。

1 个答案:

答案 0 :(得分:1)

您需要包括用户的类定义。 在您提供的代码中看不到它。 这可以解释为什么错误说明它来自“未定义”

const Model = Sequelize.Model;    
class User extends Model {}

您可以这样做:

class User extends Sequelize.Model {}

请参阅此处: https://sequelize.org/master/manual/models-definition.html

此外,看起来您正在使用Sequelize的默认模型加载器,您需要在

内定义该模型。
module.exports = (sequelize, DataTypes) => {
  const User = sequelize.define("User", {

  });

  return User
};