我具有以下结构。
function createClosure (){
var secret = "shhhhh";
return function inner(){
debugger;
console.log(secret);
};
};
var innerFunction = createClosure();
innerFunction();
不带填充的此结构的大小应为83,但是在64位处理器上编译时,大小显示为84。 编译器为pdp_address [10]分配了一个额外的字节。不确定为什么要分配此额外的字节。有人可以让我知道原因吗?
我用以下代码检查了每个成员的偏移量:
typedef struct {
int8_t tmsi[4]; /**< TMSI value. */
int8_t ptmsi[4]; /**< PTMSI value. */
int8_t gprs_attach_status;
int8_t rplmn[3]; /**< PLMN info */
uint32_t T3212_value;
uint32_t T3312_value;
uint8_t cs_reject_cause;
uint8_t ps_reject_cause;
int8_t qos[28]; /** QoS parameters for a PDP context. */
int8_t pdp_addr_len;
int8_t pdp_address[10];
uint16_t apn_addr_len; /**< APN address length. */
int8_t apn_address[20]; /**< APN address. */
}nas_ftd_umts_nas_info_s_type_v01 ;
#define OFFSETOF(TYPE, ELEMENT) ((size_t)&(((TYPE *)0)->ELEMENT))
int main()
{
temp a;
test_ping_req_msg_v01 t;
nas_ftd_umts_nas_info_s_type_v01 info;
nas_ftd_umts_network_info_s_type_v01 lte;
nas_umts_ftd_info_ind_msg_v01 ftd;
cout << sizeof(info) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, ptmsi) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, gprs_attach_status) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, rplmn) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, T3212_value) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, T3312_value) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, cs_reject_cause) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, ps_reject_cause) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, qos) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, pdp_addr_len) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, pdp_address) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, apn_addr_len) << endl;
cout << OFFSETOF(nas_ftd_umts_nas_info_s_type_v01, apn_address) << endl;
}
答案 0 :(得分:6)
uint16_t
的对齐要求是从偶数地址开始。在不填充pdp_address[10]
的情况下,您有61个字节(即奇数),直到apn_addr_len
,因此编译器用一个字节填充pdp_address
,以将apn_addr_len
放入偶数地址。>