Question

我正在使用扩展谷歌浏览器，我使用以下popup.html文件运行一个简单的扩展程序：

<script type = "text/javascript">
    alert("hi from popup.html");
</script>

<body>
Hello World
</body>

只要我将带有url的src属性添加到google jquery CDN'alert（“来自popup.html”）;'不再运行了。

我的清单文件如下：

{
  "name": "My First Extension",
  "version": "1.0",
  "description": "The first extension that I made.",
  "background_page": "background.html",
  "browser_action": {
    "default_icon": "icon.png",
"popup": "popup.html"
  },
  "permissions": [
"tabs","http://*/*","https://*/*"
  ]
}

为什么添加jquery源会破坏弹出窗口？

Answer 1

您需要将脚本分成两个语句。试试这个：

<script type="text/javascript" src="jQuery.js"></script>
<script type="text/javascript">
    alert("hi from popup.html");
</script>

谷歌浏览器扩展名：popup.html javascript vs jquery

1 个答案: