Question

尝试获取变量作为偏移值，但又返回错误，有帮助吗？谢谢

set offset_number = (select to_number(datediff(second,current_timestamp(),min("created_at"))*-1) from "PRESENTATION"."DWH"."TABLE");
-- 1607610

select $offset_number;
-- 1607610

select * from "STAGING"."DWH_STAGING"."S_TRADES" at(offset => $trade_date);
-- SQL compilation error: Invalid data type [$offset_number] in AT(OFFSET => $offset_number)

Answer 1

假设这是复制/粘贴错误：at(offset => $trade_date) 当您的错误消息引用了$offset_number时。

如果将offset_number显式转换为整数怎么办？

set offset_number = (
 select to_number(datediff(second,current_timestamp(),min("created_at"))*-1)  
   from "PRESENTATION"."DWH"."TABLE")::integer;

或

select * from "STAGING"."DWH_STAGING"."S_TRADES"   
at(offset => $offset_number::integer);

-保罗-

我可以为偏移值设置变量吗？

1 个答案: