比较Neo4j中的两个列表

Question

我有此查询返回的数据集（图像）：

MATCH(node:CXEligibilityRuleConstruct)-[:_properties]->(a)-->(spoke) with node
MATCH(node)<-[r:CXEHasChild]-(parent) where parent.nodeName='Network Segmentation' with node
Match(node)-[r:CXComponentHasCXRuleConstruct]-(cxc:CXComponentHierarchy{_type:'CXComponent'})
return node.elementLabel, collect( distinct  cxc.elementLabel)

现在，如果用户输入了一个列表，例如：['Catalyst 9300','Cisco DNA Center','DNA Premier', 'ISE Appliance']，我该如何返回与该匹配项有关的node.elementLabel？

Answer 1

假设用户列表以list parameter的形式传递，并且您想精确匹配cxc.elementLabel列表（元素顺序除外），这应该可行：

MATCH (node:CXEligibilityRuleConstruct)-[:_properties]->()-->()
MATCH (node)<-[:CXEHasChild]-(parent)
WHERE parent.nodeName = 'Network Segmentation'
WITH node
MATCH (node)-[:CXComponentHasCXRuleConstruct]-(cxc:CXComponentHierarchy)
WHERE cxc._type = 'CXComponent' AND apoc.coll.disjunction(cxc.elementLabel, $list) = []
RETURN node.elementLabel

APOC函数apoc.coll.disjunction(a, b)返回一个列表，其中包含不在a和b中的元素。

[更新]

如果您不能使用APOC，并且$list从来没有任何重复的元素，那么这应该可以工作：

MATCH (node:CXEligibilityRuleConstruct)-[:_properties]->()-->()
MATCH (node)<-[:CXEHasChild]-(parent)
WHERE parent.nodeName = 'Network Segmentation'
WITH node
MATCH (node)-[:CXComponentHasCXRuleConstruct]-(cxc:CXComponentHierarchy)
WHERE cxc._type = 'CXComponent' AND
  SIZE(cxc.elementLabel) = SIZE($list) AND
  ALL(x IN $list WHERE x IN cxc.elementLabel)
RETURN node.elementLabel