Question

我目前正在使用flex sdk 4.5（但与4.1相同）我有以下问题：

我将ItemRenderer的当前状态绑定到外部对象。该对象通过Robotlegs注入器注入mxml视图。

视图有4个状态，只要我不翻转项目本身，一切正常。在这种情况下，没有任何明显的解释，即使绑定的currentState变量未更改，currentState也会切换到defaultstate。要解决这个问题（并证明绑定状态值没有改变），我会听到当状态切换到默认状态时创建的按钮的添加事件，并强制currentState再次切换到当前值。

它有效，但显然很糟糕，有人能告诉我发生了什么吗？谢谢！

请看下面的代码：

<s:ItemRenderer xmlns:fx="http://ns.adobe.com/mxml/2009"
 xmlns:s="library://ns.adobe.com/flex/spark"
 xmlns:mx="library://ns.adobe.com/flex/mx"
 xmlns:modelviews="it.addme.MVVM.modelviews.*"
 width="150" height="100" autoDrawBackground="true"
 currentState="{modelView.currentState}"
 >

 <fx:Script>
 <![CDATA[
 import it.addme.MVVM.modelviews.AddMeButtonPresenter;

 [Inject]
 [Bindable]
 public var modelView:AddMeButtonPresenter;

 override public function set data(value:Object):void 
 {
 panel.title = value.appName;
 } 

 protected function button1_addedHandler(event:Event):void
 {//I need this to solve the roll-over problem
 currentState = modelView.currentState;
 }

 ]]>
 </fx:Script>

 <s:states>
 <s:State name="default" />
 <s:State name="USER_UNKNOWN" />
 <s:State name="USER_EXISTS" />
 <s:State name="USER_DOESNT_EXIST" />
 </s:states>

 <s:Panel left="0" top="0" width="150" height="100" id="panel">
 <s:Button includeIn="USER_UNKNOWN" label="Checking..." enabled="true" horizontalCenter="0"
 verticalCenter="0"/>
 <s:Button includeIn="USER_EXISTS" label="Unsubscribe" click="modelView.unsubscribe()"
 enabled="true" horizontalCenter="0" verticalCenter="0"/>
 <s:Button includeIn="USER_DOESNT_EXIST" label="Subscribe" click="modelView.subscribe()"
 enabled="true" horizontalCenter="0" verticalCenter="0"/>
 <s:Button includeIn="default" label="..." added="button1_addedHandler(event)"
 horizontalCenter="0" includeInLayout="false" verticalCenter="0"/>
 </s:Panel>
</s:ItemRenderer>

Answer 1

查看protected function getCurrentRendererState():String spark.components.supportClasses.ItemRenderer（documentation）的{{1}}并正确覆盖它。

滚动一个spark ItemRenderer将视图状态切换为默认值！

1 个答案: