Question

我在节点js中有一个API，当出现问题时会返回错误消息，但是当我想在PHP中使用“ file_get_contents”显示它时，它将返回“ null”。何时应该：

{" errMsg ":" Do not found information! "," Status ": 400}

http://repuveconsulta.com:3001/api/plateinfos/1?plate_number=xx&captcha_code=y78

$placa = $_POST['search_field'];
$codigo = $_POST['code'];
$id =$_POST['id'];    

$response = file_get_contents('http://repuveconsulta.com:3001/api/plateinfos/'.$id.'?plate_number='.$placa.'&captcha_code='.$codigo);
var_dump($response);   

var_dump($Array2 = json_decode($response, true));

Answer 1

我认为您会得到null，因为您的状态为400，我在本地主机上对其进行了测试，并得到以下响应：

Warning: file_get_contents(http://repuveconsulta.com:3001/api/plateinfos/1?plate_number=xx&amp;captcha_code=y78): failed to open stream: HTTP request failed! HTTP/1.1 400 Bad Request in C:\wamp64\www\****\controllers\Home.php on line 46

C：\ wamp64 \ www *** \ controllers \ Home.php：47：null

也许您可以使用curl来检查响应代码，但我不知道file_get_contents是否可行：

$url = 'http://repuveconsulta.com:3001/api/plateinfos/1?plate_number=xx&captcha_code=y78';

$ch           = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$result       = curl_exec($ch);
$status_code  = curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);

var_dump(json_decode($result, true));
var_dump($status_code);

您还可以添加：

curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 5); // The number of seconds to wait while trying to connect. Use 0 to wait indefinitely.
    curl_setopt($ch, CURLOPT_TIMEOUT, 5); // The maximum number of seconds to allow cURL functions to execute.

针对curl请求，因此当您的服务中断时，网站将一直挂起，直到出现超时错误为止

file_get_contents不返回400状态的响应

1 个答案: