如何添加Params以及如何获取String？ （java，httpclient 4.X）

Question

Code Http get request：

HttpClient httpclient = new DefaultHttpClient();

    CookieStore cookieStore = new BasicCookieStore();

    // Create local HTTP context
    HttpContext localContext = new BasicHttpContext();
    // Bind custom cookie store to the local context
    localContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore);

    HttpGet first = new HttpGet("http://vk.com");
    HttpResponse response = httpclient.execute(first, localContext);

    HttpEntity entity = response.getEntity();
    if (entity != null) {
        InputStream instream = entity.getContent();
        int l;
        byte[] tmp = new byte[2048];
        while ((l = instream.read(tmp)) != -1) {
        }
    }

如何获得响应STRING？

我需要创建请求POST，添加参数和自动重定向。

Answer 1

可能有更快的方法可以做到这一点，但这会让你得到一个字符串的响应：

        InputStream = response.getEntity().getContent();
        StringBuilder sb = new StringBuilder();
        BufferedReader r = new BufferedReader(new InputStreamReader(in));
        for (String line = r.readLine(); line != null; line = r.readLine()) {
            sb.append(line);
        }
        in.close();
        String s = sb.toString();

要创建帖子请求，请使用：

        PostMethod post = new PostMethod("http://url.com");
        post.addParameter("param1name", "param1value");

或HttpPost：http://www.androidsnippets.com/executing-a-http-post-request-with-httpclient

HttpClient应该为您处理自动重定向