我需要两次调用API,首先找到密钥,然后使用该密钥提取相关数据。
我这样做是通过订阅内部的,但是发现这是不好的编程习惯。我了解了关于flapMaps的信息,但尚未正确实现。
``打字稿
this.DrQue.clinicDoctorQueControllerFind('key', ({ "include": [{"relation":"patientQue"}] })).subscribe(data => {
this.drQue = data;
for (let i = 0; i < this.drQue.length; ++i) {
if (this.componentDr == this.drQue[i].name) {
this.indexDr = i;
i = this.drQue.length + 1;
}
}
this.patQue.patientQueCheckInControllerFind(this.drQue[this.indexDr].patientQue.id).subscribe(data => {
for (let count = 0; count < data.length; ++count) {
if (data[count].status == this.checkStatus){
this.checkInArr.push(data[count]);
}
}
});
});
``
答案 0 :(得分:4)
尝试一下:
this.DrQue.clinicDoctorQueControllerFind('key', ({ "include": [{"relation":"patientQue"}] }))
.pipe(
switchMap((data) => {
/**
* Here we manipulate our data
*/
this.drQue = data;
for (let i = 0; i < this.drQue.length; ++i) {
if (this.componentDr == this.drQue[i].name) {
this.indexDr = i;
i = this.drQue.length + 1;
}
}
/**
* Here we return new Observable stream
*/
return this.patQue.patientQueCheckInControllerFind(this.drQue[this.indexDr].patientQue.id);
})
).subscribe(data => {
/**
* Here we subscribe to the result and manipulate it
*/
for (let count = 0; count < data.length; ++count) {
if (data[count].status == this.checkStatus){
this.checkInArr.push(data[count]);
}
}
});
答案 1 :(得分:3)
通常,rxjs运算符是您的此类用例的朋友。
在此处查找文档:https://rxjs-dev.firebaseapp.com/guide/operators
在这种情况下,我建议使用switchMap并点击
this.DrQue.clinicDoctorQueControllerFind('key', ({ "include": [{"relation":"patientQue"}] })).pipe(
tap(data => {
this.drQue = data;
for (let i = 0; i < this.drQue.length; ++i) {
if (this.componentDr == this.drQue[i].name) {
this.indexDr = i;
i = this.drQue.length + 1;
}
}
}),
switchMap(data => this.patQue.patientQueCheckInControllerFind(this.drQue[this.indexDr].patientQue.id)),
tap(data => {
for (let count = 0; count < data.length; ++count) {
if (data[count].status == this.checkStatus){
this.checkInArr.push(data[count]);
}
})
).subscribe();