Question

我正在尝试找出员工时钟的开始日期和结束日期。以下是我拥有的数据的示例。

PersonID  EventTime                       ActivityCode
1         2019-07-29 00:03:03.000         7
1         2019-07-29 00:09:41.000         0
1         2019-07-29 00:01:07.000         7
1         2019-07-29 00:01:19.000         0

想要的输出：

PersonID  EventTime                   EndTime                           ActivityCode
1         2019-07-29 00:03:03.000     2019-07-29 00:09:41.000            7
1         2019-07-29 00:09:41.000     2019-07-29 00:01:07.000            0
1         2019-07-29 00:01:07.000      2019-07-29 00:01:19.000           7
1         2019-07-29 00:01:19.000                                        0

我必须根据事件时间和活动代码找到此人的开始日期和结束日期。开始日期将是事件时间列，我必须从同一列（即该行中的下一个事件时间）计算结束日期。

我已经尝试在T-SQL中使用引导函数，但是并没有给我想要的结果。

select personid, activitycode, eventtime as starttime
    , (lead(eventtime) over (order by personid)) as endtime 
from ActivityTable

如果有人对如何处理有任何想法，我将不胜感激。

Answer 1

在您的示例中，您的输出看起来有些奇怪，因为EventTime似乎在EndTime之后发生。如果您正在寻找时间顺序，并且期望这样的结果集：

然后，xQbert的评论是正确的。您只需要在Order By中添加EventTime。请参见下面的示例代码。

CREATE TABLE #T (
    PersonID INT
    ,EventTime DATETIME
    ,ActivityCode INT
)

INSERT INTO #T(
    PersonID
    ,EventTime
    ,ActivityCode
)
SELECT
    PersonID
    ,EventTime
    ,ActivityCode
FROM
    (VALUES ( 1,'2019-07-29 00:03:03.000', 7)
            ,(1,'2019-07-29 00:09:41.000', 0)
            ,(1,'2019-07-29 00:01:07.000', 7)
            ,(1,'2019-07-29 00:01:19.000', 0)) AS T (PersonID,EventTime,ActivityCode)


SELECT
    PersonID
    ,ActivityCode
    ,EventTime AS starttime
    ,(LEAD(EventTime) OVER (ORDER BY PersonID, EventTime DESC)) AS endtime
FROM
    #T;

Answer 2

我怀疑您的EventTime应该是13:00而不是01:00

示例

Declare @YourTable Table ([PersonID] varchar(50),[EventTime] datetime,[ActivityCode] int)  Insert Into @YourTable Values 
 (1,'2019-07-29 00:03:03.000',7)
,(1,'2019-07-29 00:09:41.000',0)
,(1,'2019-07-29 00:13:07.000',7)  << changed to 13
,(1,'2019-07-29 00:13:19.000',0)  << changed to 13

Select PersonID
      ,EventTime 
      ,EndTime= lead([EventTime],1) over (partition by [PersonID] order by [EventTime])
      ,ActivityCode
 From @YourTable
 Order by EventTime

返回

PersonID    EventTime                 EndTime                   ActivityCode
1           2019-07-29 00:03:03.000   2019-07-29 00:09:41.000   7
1           2019-07-29 00:09:41.000   2019-07-29 00:13:07.000   0
1           2019-07-29 00:13:07.000   2019-07-29 00:13:19.000   7
1           2019-07-29 00:13:19.000   NULL                      0

Answer 3

尝试这样。.

json

从员工时钟中查找开始日期和结束日期

3 个答案: