例如,现在每次我使用cost = get_cost()时,该函数都会通过并再次要求输入。有没有一种方法可以只保存返回值,所以我可以在另一个函数中使用该值?感谢您的所有帮助。
def get_cost():
cost = float(input('Please Enter the Cost of the Meal: '))
while cost <= 0:
print('The Cost Must Be Greater Than 0!')
cost = float(input('Please Enter the Cost of the Meal: '))
else:
return cost
def compute_tip():
cost = get_cost()
finalTip = cost * 0.18
return finalTip
def compute_tax():
cost = get_cost()
finalTax = cost * 0.0825
return finalTax
def compute_grand_total():
cost = get_cost()
finalTip = compute_tip()
finalTax = compute_tax()
grandTotal = cost + finalTip + finalTax
return grandTotal
def display_total_cost():
cost = get_cost()
finalTip = compute_tip()
finalTax = compute_tax()
grandTotal = compute_grand_total()
print('Cost\t$', format(cost, '.2f'))
print('Tip\t$', format(finalTip, '.2f'))
print('Tax\t$', format(finalTax, '.2f'))
print('Total\t$', format(grandTotal, '.2f'))
def main():
get_cost()
compute_tip()
compute_tax()
compute_grand_total()
display_total_cost()
main()
答案 0 :(得分:4)
看起来您的主要功能只需要包含一个功能调用
def main():
display_total_cost()
因为display_total_cost()
根据需要在内部调用所有其他函数。
然后,您可以将cost
作为函数参数传递给需要它的其他函数,并从所有其他函数中删除get_cost
调用。这是脚本的更新版本:
def get_cost():
cost = float(input('Please Enter the Cost of the Meal: '))
while cost <= 0:
print('The Cost Must Be Greater Than 0!')
cost = float(input('Please Enter the Cost of the Meal: '))
else:
return cost
def compute_tip(cost):
finalTip = cost * 0.18
return finalTip
def compute_tax(cost):
finalTax = cost * 0.0825
return finalTax
def display_total_cost():
cost = get_cost()
finalTip = compute_tip(cost)
finalTax = compute_tax(cost)
grandTotal = cost + finalTip + finalTax
print('Cost\t$', format(cost, '.2f'))
print('Tip\t$', format(finalTip, '.2f'))
print('Tax\t$', format(finalTax, '.2f'))
print('Total\t$', format(grandTotal, '.2f'))
def main():
display_total_cost()
# common practice is to include this line
if __name__ == "__main__":
main()
答案 1 :(得分:0)
返回值后,必须保存该值,并将其传递给其他函数。像这样:
def main():
cost = get_cost()
tip = compute_tip(cost)
tax = compute_tax(cost)
total = compute_grand_total(tip, tax)
display_total_cost(total)
但是您还必须重写函数以接受这些参数,例如:
def compute_tip(cost):
finalTip = cost * 0.18
return finalTip
答案 2 :(得分:0)
添加参数,因此您无需继续调用相同的函数。
def get_cost():
cost = float(input('Please Enter the Cost of the Meal: '))
while cost <= 0:
print('The Cost Must Be Greater Than 0!')
cost = float(input('Please Enter the Cost of the Meal: '))
else:
return cost
def compute_tip(cost):
finalTip = cost * 0.18
return finalTip
def compute_tax(cost):
finalTax = cost * 0.0825
return finalTax
def compute_grand_total(cost, finalTip, finalTax):
grandTotal = cost + finalTip + finalTax
return grandTotal
def display_total_cost(cost):
finalTip = compute_tip(cost)
finalTax = compute_tax(cost)
grandTotal = compute_grand_total(cost, finalTip, finalTax)
print('Cost\t$', format(cost, '.2f'))
print('Tip\t$', format(finalTip, '.2f'))
print('Tax\t$', format(finalTax, '.2f'))
print('Total\t$', format(grandTotal, '.2f'))
def main():
cost = get_cost()
display_total_cost(cost)
main()