使用漂亮的汤python从标签内部提取html ID

Question

我正在尝试仅提取html中的iid代码，以便可以将其附加到url并打开所需的页面。

我可以通过指定标签的类来找到所需的标签。但是我在输出中还得到了4个其他标签。我想要的只是第一个标签“ 183988596953”中的iid

我尝试使用此代码仅指定idd

rslt_table = soup.find_all("iid",{"div class": "lvpic pic img left"})

这似乎只返回一个空列表[]

当我用下面的第二行代码替换上面的代码行时，我得到的输出是我提到的带有4个标签的输出

from bs4 import BeautifulSoup
import requests
import re

urls = ['https://www.ebay.co.uk/sch/i.html?_from=R40&_trksid=m570.l1313&_nkw=goldfinger+quad']

#https://www.ebay.co.uk/sch/i.html?_from=R40&_trksid=m570.l1313&_nkw=

def find_id(urls):
    for url in urls:
        session = requests.session()
        response = session.get(url)
        #soup = BeautifulSoup(response.content, "lxml")
        soup = BeautifulSoup(response.content, "html.parser")
        rslt_table = soup.find("div", {"class": "lvpic pic img left"})
        return(rslt_table)

我的搜索网址是https://www.ebay.co.uk/sch/i.html?_from=R40&_trksid=m570.l1313&_nkw=goldfinger+quad'

全名是

<div class="lvpic pic img left" iid="183988596953">
<div class="lvpicinner full-width picW">
<a class="img imgWr2" href="https://www.ebay.co.uk/itm/GOLDFINGER-1964-Style-A-B-UK-Cinema-High-Quality-Repro-30-x-40-quad-poster/183988596953?hash=item2ad69330d9:g:rYQAAOSwrENdbmEW">
<img alt='GOLDFINGER 1964 Style A &amp; B -  UK Cinema High Quality Repro 30"x 40" quad poster' class="img" src="https://i.ebayimg.com/thumbs/images/g/rYQAAOSwrENdbmEW/s-l225.jpg"/>
</a>
</div></div>

Answer 1

您的代码已更新：

• 使用attrs返回所有属性
  • {'class': ['lvpic', 'pic', 'img', 'left'], 'iid': '183988596953'}

def find_id(urls):
    for url in urls:
        session = requests.session()
        response = session.get(url)
        soup = BeautifulSoup(response.content, "html.parser")
        return soup.find("div", {"class": "lvpic pic img left"}).attrs['iid']

iid = find_id(urls)

print(iid)

>>> '183988596953'

如果您想全部iid：

def find_id(urls):
    for url in urls:
        session = requests.session()
        response = session.get(url)
        soup = BeautifulSoup(response.content, "html.parser")
        div = s.find_all("div", attrs={'class': 'lvpic pic img left'})
        return [iid.attrs['iid'] for iid in div]