Question

我一直在为此苦苦挣扎，无法获得令人满意的结果。我有这个哈希值：

{"idprj"=>13351, "prevInicioStr"=>"21/10/2019"}
{"idprj"=>14473, "prevInicioStr"=>"22/10/2019"}
{"idprj"=>14165, "prevInicioStr"=>"23/10/2019"}
{"idprj"=>14165, "prevInicioStr"=>"23/10/2019"}
{"idprj"=>14165, "prevInicioStr"=>"28/10/2019"}
{"idprj"=>14165, "prevInicioStr"=>"28/10/2019"}
{"idprj"=>14518, "prevInicioStr"=>"29/10/2019"}
{"idprj"=>14518, "prevInicioStr"=>"29/10/2019"}
{"idprj"=>13351, "prevInicioStr"=>"05/11/2019"}
{"idprj"=>14305, "prevInicioStr"=>"06/11/2019"}
{"idprj"=>14305, "prevInicioStr"=>"08/11/2019"}
{"idprj"=>14305, "prevInicioStr"=>"13/01/2020"}

我想按'prevInicioStr'进行排序，并按'idprj'进行分组（您可以看到ID 13351没有按应有的方式分组）。为了获得此结果，我这样做：

result.sort_by { |hash| [ Date.parse(hash['prevInicioStr']), hash['idprj'] ] }

Answer 1

您必须先分组，然后再排序（实际上是对值进行排序）：

data = [{"idprj"=>13351, "prevInicioStr"=>"21/10/2019"}, {"idprj"=>14473, "prevInicioStr"=>"22/10/2019"}, {"idprj"=>14165, "prevInicioStr"=>"23/10/2019"}, {"idprj"=>14165, "prevInicioStr"=>"23/10/2019"}, {"idprj"=>14165, "prevInicioStr"=>"28/10/2019"}, {"idprj"=>14165, "prevInicioStr"=>"28/10/2019"}, {"idprj"=>14518, "prevInicioStr"=>"29/10/2019"}, {"idprj"=>14518, "prevInicioStr"=>"29/10/2019"}, {"idprj"=>13351, "prevInicioStr"=>"05/11/2019"}, {"idprj"=>14305, "prevInicioStr"=>"06/11/2019"}, {"idprj"=>14305, "prevInicioStr"=>"08/11/2019"}, {"idprj"=>14305, "prevInicioStr"=>"13/01/2020"}]
pp data.group_by { |e| e['idprj'] }
       .transform_values { |values| values.sort_by { |e| e['prevInicioStr'] } }

# {13351=>
#   [{"idprj"=>13351, "prevInicioStr"=>"05/11/2019"},
#    {"idprj"=>13351, "prevInicioStr"=>"21/10/2019"}],
#  14473=>[{"idprj"=>14473, "prevInicioStr"=>"22/10/2019"}],
#  14165=>
#   [{"idprj"=>14165, "prevInicioStr"=>"23/10/2019"},
#    {"idprj"=>14165, "prevInicioStr"=>"23/10/2019"},
#    {"idprj"=>14165, "prevInicioStr"=>"28/10/2019"},
#    {"idprj"=>14165, "prevInicioStr"=>"28/10/2019"}],
#  14518=>
#   [{"idprj"=>14518, "prevInicioStr"=>"29/10/2019"},
#    {"idprj"=>14518, "prevInicioStr"=>"29/10/2019"}],
#  14305=>
#   [{"idprj"=>14305, "prevInicioStr"=>"06/11/2019"},
#    {"idprj"=>14305, "prevInicioStr"=>"08/11/2019"},
#    {"idprj"=>14305, "prevInicioStr"=>"13/01/2020"}]}

Ruby-按ID排序并按哈希中的日期分组

1 个答案: