我希望这段代码在每个循环中读取3个字节,并且不打印,但是文件的每8000个字节左右,它只能读取两个字节:
use std::error::Error;
use std::fs::File;
use std::io::prelude::*;
use std::io::BufReader;
use std::io::BufWriter;
use std::io::SeekFrom;
use std::path::Path;
fn main() -> std::io::Result<()> {
let sequence: [u8; 3] = [1, 2, 3];
let file_path = Path::new("./test_file");
//fill a file with 1,2,3,1,2,3...
{
let mut output_file: std::io::BufWriter<std::fs::File>;
output_file = BufWriter::new(File::create(file_path)?);
for _i in 0..100000 {
match output_file.write(&sequence) {
Err(why) => panic!("could not write {}", Error::description(&why)),
Ok(_) => {}
}
}
}
//read the file 3 bytes at a time
{
let mut input_file: std::io::BufReader<std::fs::File>;
input_file = BufReader::new(File::open(file_path)?);
for i in 0..100000 {
let mut raw = [0; 3];
let result = match input_file.read(&mut raw) {
Err(why) => panic!("could not read {}", Error::description(&why)),
Ok(x) => x,
};
// print if something other than 3 bytes were read
if result != 3 {
println!(
"file pos {}, data read {}, buffer = [{},{},{}]",
i * 3,
result,
raw[0],
raw[1],
raw[2]
);
}
}
}
Ok(())
}
在装有rustc problem.rs
的Mac上编译并在./problem
上运行。
输出:
file pos 8190, data read 2, buffer = [1,2,0]
file pos 16383, data read 2, buffer = [3,1,0]
file pos 24576, data read 2, buffer = [2,3,0]
file pos 32769, data read 2, buffer = [1,2,0]
file pos 40962, data read 2, buffer = [3,1,0]
file pos 49155, data read 2, buffer = [2,3,0]
file pos 57348, data read 2, buffer = [1,2,0]
file pos 65541, data read 2, buffer = [3,1,0]
...
这似乎暗示与内部8192大小的缓冲区有关。
为什么我每次都没有3个字节?我一次读取5个字节会得到类似的结果。
答案 0 :(得分:2)
默认缓冲区大小为8KB。参见docs for BufReader::new
。
8192字节不能被3整除,因此在每个缓冲区的末尾会有几个尾随字节。
您可以使用with_capacity
constructor将缓冲区大小设置为8KB以外的值。