Question

我有进行网址请求的方法：

 public function send($httpUrl, $httpParams = [], $httpHeader = [], $waitForResponse = false)
    {
        if ($httpParams) {
            foreach ($httpParams as $key => &$val) {
                if (is_array($val)) $val = implode(',', $val);
                $post_params[] = $key . '=' . urlencode($val);
            }
            $post_string = implode('&', $post_params);
        }


        $parts = parse_url($httpUrl);

        if ($parts['scheme'] == 'https') {
            $parts['port'] = 5371;  // wymagany port dla nginx w php v 7.1
            $parts['url'] = "ssl://" . $parts['host'];
        }

        if (!$httpHeader['Method'])
            $httpHeader['Method'] = "GET";

        $fp = fsockopen($parts['url'],
            isset($parts['port']) ? $parts['port'] : 80,
            $errno, $errstr, 30);

        $out = $httpHeader['Method'] . " " . $parts['path'] . " HTTP/1.1\r\n";
        $out .= "Host: " . $parts['host'] . "\r\n";
        foreach ($httpHeader AS $k => $w) {
            if ($k == 'Method') continue;
            $out .= "$k: $w\r\n";
        }
        $out .= "Content-Type: application/x-www-form-urlencoded\r\n";
        $out .= "Content-Length: " . strlen($post_string) . "\r\n";
        $out .= "Connection: Close\r\n\r\n";
        if (isset($post_string)) $out .= $post_string;

        fwrite($fp, $out);
        if ($waitForResponse) {
            $odpowiedz = '';
            while (!feof($fp)) {
                $odpowiedz .= fgets($fp, 128);
            }
        } else {
            $odpowiedz = true;
        }
        fclose($fp);

        return $odpowiedz;
    }

问题是它返回带有标题的响应喜欢：

string(746) "HTTP/1.1 200 OK Date: Wed, 16 Oct 2019 12:17:57 GMT Server: Apache Set-Cookie: PHPSESSID=960d6fee4a2fcdc25520f75b2cd5d11a; path=/ Expires: Thu, 19 Nov 1981 08:52:00 GMT Cache-Control: no-store, no-cache, must-revalidate Pragma: no-cache Access-Control-Allow-Headers: Content-Type, Authorization Access-Control-Allow-Origin: * Access-Control-Allow-Methods: GET, POST, PUT, DELETE Content-Length: 269 Connection: close Content-Type: application/json;charset=utf-8 {"ankieta_id":6,"pytanie":"Pierwsze pytanie - dzia\u0142a?","link":"https:\/\/www.infirma.pl\/ankiety\/eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJhbmtpZXRhSWQiOjYsImtsaWVudElkIjoxLCJ1enl0a293bmlrSWQiOjEsImV4cCI6MTU3MzgyMDI3N30.4zXu0e9ns4OZC0f5ITD9XoTd8TS3zUROOSVjiKnebdU"}"

我只希望标头不是json字符串。

Answer 1

使用fread()来读取响应。使用以下代码更改fgets部分：

while (!feof($fp)) {
    $odpowiedz .= fread($this->socket, 1024);
}

然后，您可以使用以下代码仅剥离身体部位：

$crlf = "\r\n";
$position = strpos($response, $crlf.$crlf);
$content = substr($response, $position + 2 * strlen($crlf));

Answer 2

您正在使用fread()，它将读取到行终止符或EOF。这样一来，代码中就不会包含这些行。

您应该使用fread()来稍后拆分标题和正文。

带fsockopen的请求-不带标题的响应

2 个答案: