我是Android中的新蜜蜂,所以有人可以帮我解决我的问题......这里是:我使用两个AutoCompletedTextView作为“用户名”和“密码”,所以在这里我需要发送用户名和密码作为HTTP请求的JSon对象。现在如何在Json对象中绑定用户名和密码。任何帮助将非常感谢谢谢
答案 0 :(得分:1)
答案 1 :(得分:1)
试试这段代码
Button show_data;
JSONObject my_json_obj;
String path,firstname,lastname;
path = "http://192.168.101.123:255/services/services.php?id=9";
HttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000);
HttpEntity entity;
HttpResponse response = null;
HttpURLConnection urlconn;
my_json_obj = new JSONObject();
try
{
urlconn = (HttpURLConnection) new URL(path).openConnection();
urlconn.setConnectTimeout(10000);
urlconn.setDoOutput(true);
OutputStreamWriter writer = new OutputStreamWriter(urlconn.getOutputStream(), "UTF-8");
my_json_obj.put("sUserName", "test2"); my_json_obj.put("sPassword", "123456");
writer.write(my_json_obj.toString()); writer.close();
if(true) { String temp; temp = WebRequestCall(my_json_obj); //Log.i("Reply", temp); }
答案 2 :(得分:0)
您可以使用
将Json对象发送到服务器JSONObject jsonObjRecv = HttpClient.SendHttpPost(URL, jsonObjSend);
和HttpClient class
是
public class HttpClient {
private static final String TAG = "HttpClient";
public static JSONObject SendHttpPost(String URL, JSONObject jsonObjSend) {
try {
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httpPostRequest = new HttpPost(URL);
StringEntity se;
se = new StringEntity(jsonObjSend.toString());
// Set HTTP parameters
httpPostRequest.setEntity(se);
httpPostRequest.setHeader("Accept", "application/json");
httpPostRequest.setHeader("Content-type", "application/json");
httpPostRequest.setHeader("Accept-Encoding", "gzip"); // only set this parameter if you would like to use gzip compression
long t = System.currentTimeMillis();
HttpResponse response = (HttpResponse) httpclient.execute(httpPostRequest);
Log.i(TAG, "HTTPResponse received in [" + (System.currentTimeMillis()-t) + "ms]");
// Get hold of the response entity (-> the data):
HttpEntity entity = response.getEntity();
if (entity != null) {
// Read the content stream
InputStream instream = entity.getContent();
Header contentEncoding = response.getFirstHeader("Content-Encoding");
if (contentEncoding != null && contentEncoding.getValue().equalsIgnoreCase("gzip")) {
instream = new GZIPInputStream(instream);
}
// convert content stream to a String
String resultString= convertStreamToString(instream);
instream.close();
resultString = resultString.substring(1,resultString.length()-1); // remove wrapping "[" and "]"
// Transform the String into a JSONObject
JSONObject jsonObjRecv = new JSONObject(resultString);
// Raw DEBUG output of our received JSON object:
Log.i(TAG,"<JSONObject>\n"+jsonObjRecv.toString()+"\n</JSONObject>");
return jsonObjRecv;
}
}
catch (Exception e)
{
// More about HTTP exception handling in another tutorial.
// For now we just print the stack trace.
e.printStackTrace();
}
return null;
}
private static String convertStreamToString(InputStream is) {
/*
* To convert the InputStream to String we use the BufferedReader.readLine()
* method. We iterate until the BufferedReader return null which means
* there's no more data to read. Each line will appended to a StringBuilder
* and returned as String.
*
* (c) public domain: http://senior.ceng.metu.edu.tr/2009/praeda/2009/01/11/a-simple-restful-client-at-android/
*/
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
}