Question

我有下面的代码来计算时间差，但是当我运行代码时，它会打印0差。请在下面查看我的代码。

我想获取从PM（今天）到AM（第二天）的时间间隔的时间间隔。

//echo 'Hello World!';

//echo mktime('11','30','0','1','2019','1');
//echo mktime('12','30','0','1','2019','1');

//echo ("  hello ");
//echo date(time());
//echo (" hello ");
//echo date('Y-m-d H:i:s A');

$date = "2019-10-16";
$stime = "11:30:00 PM";
$etime = "12:30:00 AM";

if("PM" == date('A', strtotime($stime)) && "AM" == date('A', strtotime($etime)))
{
  //echo " Time transition ";

  //get the start date and start time merging format
  $sdatetime = date('Y-m-d H:i:s A', strtotime("$date $stime"));

  //convert the start datetime into epoch
  $startepoch = strtotime($sdatetime);

  //increment the date to get the next day date  
  $edate = date('Y-m-d', strtotime($date. ' + 1 day'));

  //get the end date and end time merged
  $edatetime = date('Y-m-d H:i:s A', strtotime("$edate $etime"));

  //convert the end datetime into epoch
  $endepoch = strtotime($edatetime);

  $timediff = ($endepoch-$startepoch)/3600.0;

  echo " Time Difference: ".$timediff;


}else{

  echo "No time transition";

}



// 24 hour format
//$time = "00:00:00";

//echo date('A', strtotime($time));

Answer 1

PHP datetime和strtotime可以使用AM和PM解析时间。 DateTime对象也可以直接比较。如果结束时间小于开始时间，则假定为第二天的结束时间。这比在AM和PM之间进行选择要好。

$date = "2019-10-16";
$stime = "11:30:00 PM";
$etime = "12:30:00 AM";

$dtStime = date_create($date." ".$stime);
$dtEtime = date_create($date." ".$etime);
if($dtEtime < $dtStime){
  $dtEtime->modify('+1 Day');
}
$diff = $dtStime->diff($dtEtime);
$seconds = $diff->h *3600 + $diff->i * 60 + $diff->s;

echo "Diff: ".$seconds." Seconds";

返回

Diff: 3600 Seconds

如何获得从PM到AM时间过渡的开始时间和结束时间之间的时差？

1 个答案: