我在Visual Studio 2017社区中使用C#。
我有一个正在运行的功能齐全的程序,我正在尝试对其进行优化。简而言之,该程序从文本文件中读取文本和数字,进行一些数学运算和重新格式化,然后输出到新的文本文件。
我要优化的部分是将文本行写入输出文件的方式。这是有效的方法:
using System.IO
// Let's start building the MA output text file now.
// Designate an output file --- put it in same directory as original files
// give MA file ame name as the original file -- but different extension.
maOutFile = dir + "\\" + serialNumber[f] + ".ma";
//Create MA header lines and write to file.
string maHeaderLine1 = "TITLE: S/N:" + serialNumber[f] + "\n";
string maHeaderLine2 = "ENGLISH(IN)/METRIC(MM) INDICATOR :IN-P\n";
// Open up the file for writing
File.WriteAllText(maOutFile, maHeaderLine1);
File.AppendAllText(maOutFile, maHeaderLine2);
上面的代码工作正常。我担心的是效率不是很高,尤其是在网络速度较慢的情况下。每次写入文件时都会打开和关闭文件。
因此,为了使运行速度更快,我想我会尝试StreamWriter。
我的StreamWriter代码如下:
// Designate an output file --- put it in same directory as the original files
// give MA file same name as the original file -- with different extension.
// maOutFile = dir + "\\" + serialNumber[f] + ".ma";
StreamWriter outfile;
outfile = dir + "\\" + serialNumber[f] + ".ma";
//Create MA header lines and write to file.
string maHeaderLine1 = "TITLE: S/N:" + serialNumber[f] + "\n";
string maHeaderLine2 = "ENGLISH(IN)/METRIC(MM) INDICATOR :IN-P\n";
// Open up the file for writing
//File.WriteAllText(maOutFile, maHeaderLine1);
//File.AppendAllText(maOutFile, maHeaderLine2);
outfile.WriteLine(maHeaderLine1);
outfile.WriteLine(maHeaderLine2);
Visual Studio不喜欢使用StreamWriter的新代码。它在“ outfile = dir +“ \” + serialNumber [f] +“ .ma”;行的等号右边的所有内容下方放置一条红线。
当我将鼠标悬停在红线代码上时,消息为“无法将类型字符串隐式转换为System.IO.StreamWriter”。
我的新代码不怎么样?
答案 0 :(得分:1)
您正在将字符串变量分配给StreamWriter对象,而不是创建StreamWriter对象。
尝试以下
using (StreamWriter sw = new StreamWriter(dir + "\\" + serialNumber[f] + ".ma"))
{
string maHeaderLine1 = "TITLE: S/N:" + serialNumber[f] + "\n";
string maHeaderLine2 = "ENGLISH(IN)/METRIC(MM) INDICATOR :IN-P\n";
// Open up the file for writing
//File.WriteAllText(maOutFile, maHeaderLine1);
sw.WriteLine(maHeaderLine1);
sw.WriteLine(maHeaderLine2);
}
答案 1 :(得分:0)
您要在此处为StreamWriter分配一个字符串:
outfile = dir + "\\" + serialNumber[f] + ".ma";
并查看您试图以流形式打开文件的代码,类似以下内容:
string outFileDir = dir + "\\" + serialNumber[f] + ".ma";
StreamWriter outFile = new StreamWriter(outFileDir);
答案 2 :(得分:0)
console.log('done.')
}