仅在递归函数中返回值

Question

我的任务是编写程序以找到最便宜的路线。唯一的问题是，汽车有一个油箱，需要加油。因此，我想到了这个想法，编写了一个递归函数来模拟加油过程并比较最终价格。代码看起来像这样：

    calcCheapest() {
    const routeBuilder = (curRoute, curPrice, curLiter) => {

        let curStation = curRoute[curRoute.length - 1];

        let newReachables = this.route[curStation].reachables;

        if (!newReachables.length) {
            if (curPrice < cheapestPrice) {
                return { curRoute: curRoute, curPrice: curPrice };
            } else {
                return { curRoute: [], curPrice: Infinity};
            }
        }

        else return newReachables.map(reachable => {

            // multiple comparisons on how to refule

            return routeBuilder([...curRoute, reachable], newPrice, newLiters)
        })
    }


    var cheapestPrice = Infinity;

    var a = routeBuilder([this.start], 0, this.curLiter);
    console.log(a);

}

但是我得到的“ a”变量是：

    (6)[
    0: (6)[
        0: (6)[
            0: (6)[
                0: (5)[
                    ...... 
                        [
                            curPrice: 271271.03, curRoute: Array(11)[0, 194, 1305, … ]
                        ]
                    …]
                …]
            …]
        …]
    …]

而且我不知道如何只返回值。如果我拿走地图前面的返回值，则我得到的“ a”是不确定的。