Question

我有从原始文件生成行列表的python代码，并且我想搜索特定的列字段[第4列字段，其中第二个字段具有IT，第5列字段中的第二个字段具有FW.O。 ]并从外部文件内容字段和打印行进行匹配。

Select distinct s.salesman_id, name, city,
    case when c.city is not null then 'Match' else 'No Match' end as City_Match
from salesman s
left join customer c on s.city = c.city;

如果“ L”第二列字段为“ IT”，则L = '''SET,FW.O,AS,num:+18700000,num:+12355, SET,IT,AS,num:+22211111,num:+12355, SET,FW.O,AS,num:+177232,num:+12355, SET,IT,AS,num:+368399793,num:+12355, '''.split() FWmatch = open("fwfields.txt").readlines() ITmatch = open("itfields.txt").readlines() for row in L: if row[1] == "IT": result = [i for i in L if any(x.replace('\n','') in i.split(',')[3] for x in ITmatch)] elif row[1] == "FW.O": result = [i for i in L if any(x.replace('\n','') in i.split(',')[4] for x in FWmatch)] print('\n'.join(result))应该在第五列字段中查找。

如果“ L”第二列字段为“ FW.O”，ITmatch应该在第五列字段中查找。

FWmatch

cat fwfields.txt

num:+12 num:+123

cat itfields.txt

由于我的代码无法正常工作，并且未定义变量输出，因此未定义为“输出”的错误。如果我删除“ L”处的.split（），则会出现IndexError。必需的输出：

num:+222
num:+333

Answer 1

2659,2623.5,2749.5,2826.5,2775,2795,2810,2845,2827,2847,2854,2897.5,2905,2925,2902.5,2869.5

3342.5,3386,3385,3353,3300,3190,3087.5,3092,3170,3225,3340,3315,3396,3470,3480,3380

2996,2989,2953,2950,2884.5,2829,2785,2908,2850,2761,2997.5,3020,2952,2997.5,2952,2923.5

2804.5,2850.5,2850,2850,2867,2940,2905,2945,2938,2860,2884,2946,2938,2986.5,2931.5,3032.5

2800,3074,2950,2850,2850,2875,2757,2716,2738.5,2696,2809,2891,3000,2960,2950,2831

3215,3250,3290,3260,3200,3350,3507.5,3301,3276,3320,3550,3500,3530,3498.5,3505,3605

2597.5,2649,2625.5,2890,3325,3200,3010,2850,2800,2745,2695,2695,2850,2850,2860,2695

2783.5,2800,2812,2809,2813.5,2817,2815,2849,2850,2927,2810,2890,2910,2996,2950,2897

2350,2350,2350,2475,2400,2495,2567.5,2525,2400,2350,2487.5,2395,2397.5,2450,2562.5,2500

3152.5,3015,3060,3027.5,2950,3000,3002.5,3022.5,2865,2850,2825,2895,3020,3022.5,3110,3185

3337,3500,3484,3519,3393.5,3295,3062.5,3057,3123.5,3103,3079,3216,3221,3200,3214,3405.5

3180,3325,3495,3488.5,3271.5,3216,3235,3216,3300,3405,3388.5,3600,3915,3629.5,3541,3405

2800,3049,3000,3032,2995,2987.5,2850,3000,3000,2895,2992.5,3080,3378.5,3094.5,3056,3150

2871.5,2850,2751,2710,2800,2875,2845,2700,2784.5,2749,2800,2875,2905,3028,3100,3100

3552.5,3550,3540,3510,3495,3510,3512.5,3525,3300,3270,3250,3182.5,3200,3200
,3250,3200

3397.5,3389,3450,3400,3300,3500,3495,3497.5,3395,3595,3350,3350,3425,3399.5,3364.5,3325.5

3550,3472,3493,3344.5,3332,3251,3270.5,3358,3370.5,3465.5,3495,3495,3500,3495,3458,3550

2805,2833,2900,2930,2795,2800,2890,2949,2800,2850,2839,2900,2850,2995,3087.5,2950.5

3495,3530,3610,4200,3990,3925,4000,3785,3792.5,3525,3495,3850,3900,4137.5,4000,4200

3545,3355,3305,3143,3220,3200,3180,3639,3260,3265,3510,3575,3695,3482.5,3600,3292.5

2995,3180,3225,3204,3219,3109,2998.5,2995,3200,3193.5,3161,3195,3200,3338.5,3200,3176

3599,3641,3796,3650,3552.5,3570,3535,3465,3400,3316,3640,3770,3440,3790,3815,3692.5

3500,3509.5,3519,3717.5,3495,3435,3285,3162.5,3425,3375,3410,3472.5,3600,3980,3657.5,3650

3773,3696,3708,3778,3689,3625,3516,3518.5,3647,3596,3685,3945,3811,3848,3699,4021.5

要考虑的要点：

从每行中删除结束行
您无法“重用”打开，因为它会读取文件。需要将其阅读到列表中，以后可以多次使用。

这有效：

$ cat fwfields.txt
num:+17
num:+18`

$ cat itfields.txt
num:+222
num:+333

lines="""SET,FW.O,AS,num:+18700000,num:+12355,
SET,IT,AS,num:+22211111,num:+12355,
SET,FW.O,AS,num:+177232,num:+12355,
SET,IT,AS,num:+368399793,num:+12355,
""".split()

def chomp(x):
    return x.replace('\n','')

这不是：

FWmatch = open("fwfields.txt").readlines()
ITmatch = open("itfields.txt").readlines()
result1 = [i for i in lines if any(chomp(x) in i for x in FWmatch)]
result2 = [i for i in lines if any(chomp(x) in i for x in ITmatch)]
print('\n'.join(result1+result2))

Answer 2

您的代码失败，因为result尚未初始化，并且条件永远不成立，因为row [1]是row的第一个字符。您应该改用row.split（'，'）[1]。这是一个有效的代码：

L = '''SET,FW.O,AS,num:+18700000,num:+12355,
SET,IT,AS,num:+22211111,num:+12355,
SET,FW.O,AS,num:+177232,num:+12355,
SET,IT,AS,num:+368399793,num:+12355,
'''.split()

def chomp(x):
    return x.replace('\n','')

FWmatch = open("fwfields.txt").readlines()
ITmatch = open("itfields.txt").readlines()
result=[]
for row in L:
      country = row.split(',')[1]
      if country == "IT":
          codes = ITmatch
      elif country == "FW.O":
          codes = FWmatch
      num = row.split(',')[3]
      if any(chomp(c) in num for c in codes):
          result.append( row)
print('\n'.join(result))

Python：“ FOR”循环以打印基于行的列字段匹配

2 个答案: