表单中的SwiftUI选择器不显示所选行

时间:2019-10-16 05:17:31

标签: ios swift forms swiftui picker

我正在尝试使用一个选择器来显示当前选中的选项。

尝试以下代码,该代码可以正确选择正确的选项,但选择器不会显示选择了哪个选项:

import SwiftUI

struct ContentView: View {
@State var selectedIndex: Int = 0

let strings: [String] = {
    var strings: [String] = []
    for i in 0..<10 {
        strings.append("\(i)")
    }
    return strings
}()

var body: some View {
    NavigationView {
        VStack {
            Form {
                Picker(selection: $selectedIndex,
                       label: Text("Selected string: \(strings[selectedIndex])")) {
                    ForEach(0..<strings.count) {
                        Text(self.strings[$0]).tag($0)
                    }
                }
            }
        }
        .navigationBarTitle("Form Picker",
                            displayMode: NavigationBarItem.TitleDisplayMode.inline)
    }
}

}

struct ContentView_Previews: PreviewProvider {
    static var previews: some View {
        ContentView()
    }
}

有人知道可能出什么问题吗?使用Xcode 11.1和iOS 13.1可以观察到

2 个答案:

答案 0 :(得分:2)

我创建了一个简单的选择器,我称之为“ ListPicker”,它应该符合要求。我已经编写了它,因此它可以很好地在Form中工作;如果您需要表格之外的内容,则必须进行修改。如果您发现任何改进代码的方法,请添加注释;对于我们所有人来说,这仍然是一次学习经历。

// MARK: - LIST PICKER (PUBLIC)

struct ListPicker<Content: View>: View {
    @Binding var selectedItem: Int
    var label: () -> Content
    var data: [Any]

    var selectedLabel: String {
        selectedItem >= 0 ? "\(data[selectedItem])" : ""
    }

    var body: some View {
        NavigationLink(destination: ListPickerContent(selectedItem: self.$selectedItem, data: self.data)) {
            ListPickerLabel(label: self.label, value: "\(self.selectedLabel)")
        }
    }
}

// MARK: - INTERNAL

private struct ListPickerLabel<Content: View>: View {
    let label: () -> Content
    let value: String

    var body: some View {
        HStack(alignment: .center) {
            self.label()
            Spacer()
            Text(value)
                .padding(.leading, 8)
        }
    }
}

private struct ListPickerContentItem: View {
    let label: String
    let index: Int
    let isSelected: Bool
    var body: some View {
        HStack {
            Text(label)
            Spacer()
            if isSelected {
                Image(systemName: "checkmark")
                    .foregroundColor(.accentColor)
            }
        }.background(Color.white) // so the entire row is selectable
    }
}

private struct ListPickerContent: View {
    @Environment(\.presentationMode) var presentationMode
    @Binding var selectedItem: Int
    var data: [Any]
    var body: some View {
        List {
            ForEach(0..<data.count) { index in
                ListPickerContentItem(label: "\(self.data[index])", index: index, isSelected: index == self.selectedItem).onTapGesture {
                    self.selectedItem = index
                    self.presentationMode.wrappedValue.dismiss()
                }
            }
        }
    }
}

然后您可以像这样使用它:

@State var selectedCar: Int = 0
let cars = ["Jaguar", "Audi", "BMW", "Land Rover"]

Form {
    ListPicker(
        selectedItem: self.$selectedCar, 
        label: {
            Text("Cars")
        }, 
        data: self.cars
    )
}

答案 1 :(得分:1)

这是Xcode 11.1中的错误,只需将其更新为Xcode 11.2,一切都会好