如何从其他文件调用此覆盖功能

时间:2019-10-15 11:20:04

标签: ios swift

我正在尝试从另一个文件调用函数。另一个文件具有我需要的功能,而swift不支持多重继承。

我正在尝试合并此文件-

import XLPagerTabStrip
//Delete UIViewController, and Extend //ButtonBarPagerTabStripViewController instead
class ParentViewController: ButtonBarPagerTabStripViewController {
    let purpleInspireColor = UIColor(red:0.13, green:0.03, blue:0.25, alpha:1.0)
    override func viewDidLoad() {
          super.viewDidLoad()

    // change selected bar color
    settings.style.buttonBarBackgroundColor = .white
    settings.style.buttonBarItemBackgroundColor = .white
    settings.style.selectedBarBackgroundColor = purpleInspireColor
    settings.style.buttonBarItemFont = .boldSystemFont(ofSize: 14)
    settings.style.selectedBarHeight = 2.0
    settings.style.buttonBarMinimumLineSpacing = 0
    settings.style.buttonBarItemTitleColor = .black
    settings.style.buttonBarItemsShouldFillAvailiableWidth = true
    settings.style.buttonBarLeftContentInset = 0
    settings.style.buttonBarRightContentInset = 0
    changeCurrentIndexProgressive = { [weak self] (oldCell: ButtonBarViewCell?, newCell: ButtonBarViewCell?, progressPercentage: CGFloat, changeCurrentIndex: Bool, animated: Bool) -> Void in
    guard changeCurrentIndex == true else { return }
    oldCell?.label.textColor = .black
    newCell?.label.textColor = self?.purpleInspireColor
    }
    }

    override func viewControllers(for pagerTabStripController: PagerTabStripViewController) -> [UIViewController] {
    let child_1 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Phone")
    let child_2 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Email")
    return [child_1, child_2]
    }
}

带有此文件-


import Foundation
import UIKit

class SignupViewController : UIViewController {
    override func viewDidLoad() {
        super.viewDidLoad()
    }
    @IBAction func loginTapped(_ sender: Any) {
           let loginViewController = storyboard?.instantiateViewController(withIdentifier: "LoginViewController") as! LoginViewController
           present(loginViewController,animated: true, completion: nil)
       }
    override func viewControllers(for pagerTabStripController: PagerTabStripViewController) -> [UIViewController] {
    let child_1 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Phone")
    let child_2 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Email")
    return [child_1, child_2]
    }
}

但是,它们从两个不同的基类继承,所以什么都没有起作用。

我想将这两个类放置在单独的文件中,并从需要使用的文件中调用该类中的函数,但是在调用此特定函数时,参数存在问题。

    override func viewControllers(for pagerTabStripController: PagerTabStripViewController) -> [UIViewController] {
    let child_1 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Phone")
    let child_2 = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Email")
    return [child_1, child_2]
    }

1 个答案:

答案 0 :(得分:0)

您可以使用通用代码创建一些全局函数(在任何类之外),据我所知,您不需要任何参数

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并从func instantiatePhoneAndMailViewControllers() -> [UIViewController] { return [UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Phone"), UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "Email")] } 等内部调用它。例如

viewControllers(for:)