我正在尝试在python中创建某种“截止日期时钟”。 关于时差计算有很多主题,我遵循了一些主题并将这些代码放在一起:
import datetime
from dateutil.relativedelta import relativedelta
# Get current time:
today = datetime.date.today()
timenow = datetime.datetime.now()
current_time = str(today) + " " + str(timenow.strftime("%H:%M:%S"))
# Set deadline:
deadline = "2019-12-12 15:00:00"
# Calculate difference:
start = datetime.datetime.strptime(current_time,'%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(deadline, '%Y-%m-%d %H:%M:%S')
diff = relativedelta(ends, start)
print("Now: " + current_time)
print("Deadline: " + deadline)
print(str(diff.days) + " days. "
+ str(diff.hours) + " hours. "
+ str(diff.minutes) + " minutes. "
+ str(diff.seconds) + " seconds. "
)
但是问题是,它将始终显示最多一个月的差额...那么问题出在哪里?
答案 0 :(得分:1)
只需用开始日期减去结束日期即可。
import datetime
today = datetime.date.today()
timenow = datetime.datetime.now()
deadline = "2019-12-12 15:00:00"
current_time = str(today) + " " + str(timenow.strftime("%H:%M:%S"))
start = datetime.datetime.strptime(current_time,'%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(deadline, '%Y-%m-%d %H:%M:%S')
print(start - ends)
如注释中所建议,您实际上并不需要分别使用.today()
和.now()
,.now()
返回当前日期和时间作为datetime对象本身。 / p>
import datetime
timenow = datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S')
deadline = "2019-12-12 00:00:00"
start = datetime.datetime.strptime(timenow,'%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(deadline, '%Y-%m-%d %H:%M:%S')
print(start - ends)