我使用symfony 4.1.13和FOSUser v2.1.2 尝试清除缓存时出现此错误。
您请求的服务“ fos_user.manager”不存在。
这是我的控制器功能
/**
* Create New User
* @Rest\Post("/user/create")
* @param Request $request
* @param UserManager $userManager
* @return View
*/
public function createAction(Request $request, UserManager $userManager): View
{
[...]
$userManager->updatePassword($user);
[...]
return View::create($user, Response::HTTP_OK);
}
该服务应存在:
bin/console debug:container
FOS\UserBundle\Model\UserManager alias for "fos_user.manager"
这是config / packages / fos_user.yaml的内容
# FOSUser
fos_user:
db_driver: orm
firewall_name: main
user_class: App\Entity\User
from_email:
address: "noreply@yourcompany.com"
sender_name: "No Reply"
Service.yaml
parameters:
locale: 'en'
services:
# default configuration for services in *this* file
_defaults:
autowire: true # Automatically injects dependencies in your services.
autoconfigure: true # Automatically registers your services as commands, event subscribers, etc.
public: false # Allows optimizing the container by removing unused services; this also means
# fetching services directly from the container via $container->get() won't work.
# The best practice is to be explicit about your dependencies anyway.
# makes classes in src/ available to be used as services
# this creates a service per class whose id is the fully-qualified class name
App\:
resource: '../src/*'
exclude: '../src/{DependencyInjection,Entity,Migrations,Tests,Kernel.php}'
# controllers are imported separately to make sure services can be injected
# as action arguments even if you don't extend any base controller class
App\Controller\:
resource: '../src/Controller'
tags: ['controller.service_arguments']
# add more service definitions when explicit configuration is needed
# please note that last definitions always *replace* previous ones
sensio_framework_extra.view.listener:
alias: Sensio\Bundle\FrameworkExtraBundle\EventListener\TemplateListener
FOS\OAuthServerBundle\Model\AccessTokenManagerInterface:
alias: fos_oauth_server.access_token_manager.default
FOS\UserBundle\Model\UserManager:
alias: fos_user.manager
答案 0 :(得分:0)
我通过创建服务(用户服务)并注入UserManager来解决问题
service.yaml
If ( (Get-ADUser -Filter { displayName -eq $user}) -AND ($Returner -eq "Yes")) {
$Check = Get-ADUser -Filter{displayName -eq $user} -Properties SamAccountName
$sam = $check.SamAccountName
$sam
}
UserService.php
App\Service\UserService:
arguments:
$userManager: '@fos_user.user_manager'