Question

Laravel不会保存一对多关系

我尝试使用push（）和add（），但即使使用save（）方法也无法正常工作。

我附加了Agent和该代理应该具有多个合同或根本没有合同的合同模型这是我的解决方案，但是合同没有保存到代理商！

//Agent class
<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Agent extends Model
{
    protected $table = "agent";
    protected $fillable = [
        'agent_name', 'agent_website', 'agent_main_contact_name' ,'agent_moto','agent_business', 'tier', 'class', 'status', 'agent_contact_info', 'agent_image_path','contract'
    ];

    // protected static function boot()
    // {
    //     parent::boot();
    //     //fired whenever a new user is created
    //     static::created(
    //         function ($agent){
    //             $agent->contracts()->create([
    //                 'contract_name' => 'No Contract',
    //             ]
    //         );
    //         //Mail::to($agent->email)->send(new NewUserWelcomeMail());
    //         }
    //     );
    // }

    public function contracts(){
        return $this->hasMany(Contract::class)->orderBy('created_at', 'DESC');
    }

}
// Contract model

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Contract extends Model
{
    protected $fillable = [
        'contract_name', 'contract_start_date', 'contract_end_date' ,'contract_status','contract_description'];
    protected $table = "contract";
    protected $guarded =[];
    public function agent()
    {
        return $this->belongsTo(Agent::class);
    }

}


//AgentController where the Agent is created
 public function store(Request $request)
    {
        //dd($request->contract);
        $this->validate($request, ['agentName' => 'required', 'agentBusiness' => 'required', 'status' => 'required']);

        $agent = new Agent();
        $agent->agent_name = $request->agentName;
        $agent->agent_website = $request->agentWebsite;
        $agent->agent_main_contact_name = $request->agentMainContactName;
        $agent->agent_moto = $request->agentMoto;
        $agent->agent_business = $request->agentBusiness;
        $tierId = $request->tier;
        $classId = $request->class;
        $statusId = $request->status;
        $agent->agent_contact_info = $request->agentContactInfo;
        $contractId= $request->contract;

        // $data = [
        //     'image' => '',
        // ];
        try
        {
            //dd($request->contract);
           // dd($contractId);
            $contract = Contract::find($contractId);
            //dd($contract);
            // $tier = Tier::find($tierId);
            // $class = Classes::find($classId);
            // $status = Status::find($statusId);
            $agent->contracts->push($contract);

            //dd($contract);


        }
        // catch(Exception $e) catch any exception
        catch(ModelNotFoundException $e)
        {

        }
        $tiers = Tier::select('tier_name')->where('id', $tierId)->get('tier_name');
        foreach($tiers as $tier) {
            $tierName = $tier->tier_name;
        }
        $classes = Classes::select('class_name')->where('id', $classId)->get();
        foreach($classes as $class) {
            $className = $class->class_name;
        }
        $statuss = Status::select('status_name')->where('id', $statusId)->get();

        foreach($statuss as $status) {
            $statusName = $status->status_name;
        }
        $agent->tier = $tierName;
        $agent->class = $className;
        $agent->status = $statusName;



        $agent->save();
        //dd($agent);

        session()->flash('Success', 'Agent Added Successfully');

        return back();

    }

Answer 1

这为我解决了 // dd（$ request-> contract）; // dd（$ contractId）; $ agent-> save（）; $ contract = Contract :: find（$ contractId）; // dd（$ contract）; // $ tier = Tier :: find（$ tierId）; // $ class = Classes :: find（$ classId）; // $ status = Status :: find（$ statusId）; $ agent-> contracts（）-> save（$ contract）; $ contract-> save（）; // dd（$ contract）;

Laravel不会保存一对多关系

1 个答案: