我想使用此webflux客户端代码发送带有回复和不回复的POST请求。我尝试了以下代码实现:
public class RestClientBuilder {
private String token;
private String username;
private String password;
private URL gatewayUrl;
private SslContextBuilder sslContextBuilder;
public static RestClientBuilder builder() {
return new RestClientBuilder();
}
public RestClientBuilder token(String token) {
this.token = validateAndTrim(token, "Token");
return this;
}
public RestClientBuilder usernamePassword(String username, String password) {
this.username = validateAndTrim(username, "Username");
this.password = validateAndTrim(password, "Password");
return this;
}
private String validateAndTrim(String value, final String parameter) {
if (value == null || value.trim().isEmpty()) {
throw new IllegalArgumentException(parameter + " is empty");
}
return value.trim();
}
public RestClientBuilder gatewayUrl(String gatewayUrl) {
String urlSt = validateAndTrim(gatewayUrl, "Gateway URL");
try {
this.gatewayUrl = new URL(urlSt);
} catch (MalformedURLException e) {
throw new IllegalArgumentException("Malformed URL: " + urlSt, e);
}
return this;
}
public RestClientBuilder truststore(File truststoreFile) {
getSslContextBuilder().trustManager(truststoreFile);
return this;
}
public RestClientBuilder sslCertificate(File keyCertChainFile, File keyFile, String keyPassword) {
getSslContextBuilder().keyManager(keyCertChainFile, keyFile, keyPassword);
return this;
}
public RestClient build() throws SSLException {
SslContext sslContext = sslContextBuilder != null ? sslContextBuilder.build() : null;
return new RestClient(gatewayUrl.toString(), token, username, password, sslContext);
}
private SslContextBuilder getSslContextBuilder() {
if (sslContextBuilder == null) {
sslContextBuilder = SslContextBuilder.forClient();
}
return sslContextBuilder;
}
}
其余客户的实施情况
public class RestClient {
private WebClient client;
private String gatewayUrl;
public RestClient(String gatewayUrl, String token, String username, String password, SslContext sslContext) {
this.gatewayUrl = gatewayUrl;
WebClient.Builder builder = WebClient.builder().baseUrl(gatewayUrl);
if (sslContext != null) {
HttpClient httpClient = HttpClient.create().secure(sslContextSpec -> sslContextSpec.sslContext(sslContext));
ClientHttpConnector httpConnector = new ReactorClientHttpConnector(httpClient);
builder.clientConnector(httpConnector);
}
if (username != null && password != null) {
builder.filter(basicAuthentication(username, password));
}
client = builder.build();
}
public Mono<Void> executeOnly(ReportRequest transaction) {
Mono<ReportRequest> transactionMono = Mono.just(transaction);
return client.post().uri(gatewayUrl)
.accept(MediaType.APPLICATION_XML)
.contentType(MediaType.APPLICATION_XML)
.body(transactionMono, ReportRequest.class)
.retrieve()
.bodyToMono(Void.class);
}
}
进行远程呼叫:
public class ReportingProcessor {
private String URL2 = "......";
public void collectEnvironmentData() throws JAXBException {
ReportRequest report = new ReportRequest();
report.setVersion("1.0");
RestClient client = null;
try {
client = RestClientBuilder.builder()
.gatewayUrl(URL2)
// .token(contract.getTerminal_token())
// .usernamePassword("user", "password")
// .truststore(new File("server.pem"))
// .sslCertificate(new File("client.pem"), new File("clientKey.p8"), "secret")
.build();
} catch (SSLException e) {
e.printStackTrace();
}
Mono<Void> result = client.executeOnly(report);
Void response = result.block();
}
删除Void response = result.block();
后,请求将不会发送。我找不到原因。您能给我一些建议,如何在不使用block()
的情况下使客户端代码正常工作。
答案 0 :(得分:2)
每当您使用Spring-webflux时,都必须牢记一件事。也就是说,您不必打断您的连锁店。因为有必要,应该有人在您的链上致电订阅。因为它适用于RXJava规范。
如果您断链了,那么您必须致电block()
,此电话不推荐。
您必须按照以下方式修改代码。
让我们考虑一下,有一个处理程序正在对collectEnvironmentData()
方法进行调用,而您的方法正在对远程服务进行调用。
public Mono<ServerResponse> handelerMethod(ServerRequest request){
return collectEnvironmentData().flatMap(aVoid -> ServerResponse.ok().build());
}
您的方法应修改为
public Mono<Void> collectEnvironmentData() throws JAXBException {
ReportRequest report = new ReportRequest();
report.setVersion("1.0");
RestClient client = null;
try {
client = RestClientBuilder.builder()
.gatewayUrl(URL2)
// .token(contract.getTerminal_token())
// .usernamePassword("user", "password")
// .truststore(new File("server.pem"))
// .sslCertificate(new File("client.pem"), new File("clientKey.p8"),
//"secret").build();
} catch (SSLException e) {
e.printStackTrace();
}
return client.executeOnly(report);
}
以上述方式更改您的实现,希望它能起作用。
答案 1 :(得分:1)
我将如何实现您的方法:
public Mono<Void> executeOnly(ReportRequest transaction) {
Mono<ReportRequest> transactionMono = Mono.just(transaction);
return client.post().uri(gatewayUrl)
.accept(MediaType.APPLICATION_XML)
.contentType(MediaType.APPLICATION_XML)
.body(transaction, ReportRequest.class)
.exchange()
.then();
}
然后我将按以下方式使用它:
client.executeOnly(report).subscribe()
答案 2 :(得分:0)
将method return type
更改为Mono<Void>
以进行端到端流式传输。
public void collectEnvironmentData() throws JAXBException {
ReportRequest report = new ReportRequest();
report.setVersion("1.0");
RestClient client = null;
try {
client = RestClientBuilder.builder()
.gatewayUrl(URL2)
.build();
} catch (SSLException e) {
e.printStackTrace();
}
return client.executeOnly(report);
}
或者您也可以订阅Mono
client.executeOnly(report).subscribe();