Question

在熊猫数据框列中，我需要从数千个公司名称的末尾删除诸如LLC，INC，CO之类的数千个常用词。以下内容删除了任何位置的常用词：

toexlude = dfwcomwords['ending'].tolist()

data['names'] = data['names'].apply(lambda x: ' '.join([word for word in x.split() if word not in (toexclude)]))

但是我只想删除名称末尾的单词，即“ INC INTERNATIONAL LLC”应为“ INC INTERNATIONAL”。（以上内容使其为“国际”。）任何帮助将不胜感激。

编辑：按照下面的@ba_ul建议，我收到不平衡的括号错误

for word in toexclude:
    data['names'] = data['names'].apply(lambda x: re.sub(rf'{word}$', '', x, flags=re.IGNORECASE))

Traceback (most recent call last):

  File "<ipython-input-139-c68049bc0f0d>", line 2, in <module>
    data['names'] = data['names'].apply(lambda x: re.sub(rf'{word}$', '', x, flags=re.IGNORECASE))

  File "/anaconda3/envs/pandas/lib/python3.7/site-packages/pandas/core/series.py", line 4042, in apply
    mapped = lib.map_infer(values, f, convert=convert_dtype)

  File "pandas/_libs/lib.pyx", line 2228, in pandas._libs.lib.map_infer

  File "<ipython-input-139-c68049bc0f0d>", line 2, in <lambda>
    data['names'] = data['names'].apply(lambda x: re.sub(rf'{word}$', '', x, flags=re.IGNORECASE))

  File "/anaconda3/envs/pandas/lib/python3.7/re.py", line 192, in sub
    return _compile(pattern, flags).sub(repl, string, count)

  File "/anaconda3/envs/pandas/lib/python3.7/re.py", line 286, in _compile
    p = sre_compile.compile(pattern, flags)

  File "/anaconda3/envs/pandas/lib/python3.7/sre_compile.py", line 764, in compile
    p = sre_parse.parse(p, flags)

  File "/anaconda3/envs/pandas/lib/python3.7/sre_parse.py", line 944, in parse
    raise source.error("unbalanced parenthesis")

error: unbalanced parenthesis

Answer 1

您可以检查word的两个条件：（1）是否在toexclude中；（2）它是否是公司名称中的最后一个单词。

toexlude = dfwcomwords['ending'].tolist()

def remove_suffix(x):
    x_list = x.split()
    return ' '.join([word for index, word in enumerate(x_list) if not (word in toexclude and index == len(x_list) - 1)])

data['names'] = data['names'].apply(remove_suffix)

编辑：对于包含空格的后缀，可以先使用正则表达式和pandas的str.replace函数将其删除。

data['names'] = data['names'].str.replace('S. A. R. L.$', '')

# If you have multiple such unusual suffixes, you can chain all of them together
data['names'] = data['names'].str.replace('S. A. R. L.$', '').str.replace('L L C$', '')

正则表达式中的

$可确保您仅删除名称末尾出现的内容。

编辑＃2：基于新注释，纯正则表达式解决方案可能是最好的。只有三行，应该涵盖所有情况。

import re

for word in toexclude:
    data['names'] = data['names'].apply(lambda x: re.sub(r'\b{}$'.format(re.escape(word)), '', x, flags=re.IGNORECASE))

Answer 2

如下更改支票：

data['names'] = data['names'].apply(
    lambda x: ' '.join([word for i, word in enumerate(x.split()) if not (
        i == len(x.split()) - 1 and word in toexclude)]))

Python：如何从公司名称中删除常用词列表？

2 个答案: