Question

我继续使用以下代码将Geocoder定义为未定义。我想简单地从lat和long获取一个地方的地址。行Geocoder geocoder = new Geocoder（this，Locale.ENGLISH）;总是回归原来的。

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    /* Use the LocationManager class to obtain GPS locations */
    LocationManager mlocManager =
    (LocationManager)getSystemService(Context.LOCATION_SERVICE);
    LocationListener mlocListener = new MyLocationListener();
    mlocManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 600000, 1000, mlocListener);

/* Class My Location Listener */
public class MyLocationListener implements LocationListener
{
@Override
public void onLocationChanged(Location loc)
{
loc.getLatitude();
loc.getLongitude();
Geocoder geocoder = new Geocoder(this, Locale.ENGLISH);
currentLatitude = loc.getLatitude();
currentLongitude = loc.getLongitude();

try {
      List<Address> addresses = geocoder.getFromLocation(currentLatitude, currentLongitude, 1);

      if(addresses != null) {
       Address returnedAddress = addresses.get(0);
       StringBuilder strReturnedAddress = new StringBuilder("Address:\n");
       for(int i=0; i<returnedAddress.getMaxAddressLineIndex(); i++) {
        strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n");
       }
       myAddress.setText(strReturnedAddress.toString());
      }
      else{
       myAddress.setText("No Address returned!");
      }
     } catch (IOException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
      myAddress.setText("Canont get Address!");
     }

Answer 1

那是因为它未定义：http://developer.android.com/reference/android/location/Geocoder.html显示了2个构造函数。一个接受Context，另一个接受Context和Locale，但关键是你在MyLocationListener类中创建它。试试这个：

Geocoder geocoder = new Geocoder(<ACTIVITY CLASS NAME>.this, Locale.ENGLISH);

代替。

出于性能原因，您可能希望在Geocoder类的构造函数中创建MyLocationListener的单个实例，而不是每次获得位置更新时都生成一个。

构造函数Geocoder（）未定义

1 个答案: