Question

我有一些PHP代码，可以根据照片集检索一组图像。我想操纵这段代码，以便从搜索词中抓取一组图片。

我知道你可以使用内置于api中的方法：flickr.photos.search

只是想知道如何将它应用于此代码

 <?php
  $params = array(
'api_key'   => '2292bec0973f91d9f62fb606f85ee031',
'method'    => 'flickr.photosets.getPhotos',
'photoset_id'   => '72157622566216264',
'extras'    => 'original_format',
'format'    => 'php_serial'
  );
  $encoded_params = array();
  foreach ($params as $k => $v){ $encoded_params[] = urlencode($k).'='.urlencode($v); }

   $ch = curl_init();
   $timeout = 5; // set to zero for no timeout
   curl_setopt ($ch, CURLOPT_URL, 'http://api.flickr.com/services/rest/?'.implode('&',             $encoded_params));
   curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
   curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
   $file_contents = curl_exec($ch);
   curl_close($ch);

   $rsp_obj = unserialize($file_contents);

   if ($rsp_obj['stat'] == 'ok') {

    $photos = $rsp_obj["photoset"]["photo"];

echo "
     <ul>";

foreach($photos as $photo) {

           $farm              = $photo['farm'];
           $server            = $photo['server'];
           $photo_id          = $photo['id'];
           $secret            = $photo['secret'];
           $photo_title       = $photo['title'];

         echo '<li><img          src="http://farm'.$photo['farm'].'.static.flickr.com/'.$photo['server'].'/'.$photo['id'].'_'.$photo['secret'].'_t.jpg" alt="'.$photo['title'].'" ></li>';

     }
       echo "
           </ul>

            ";

} else {
        echo "Error getting photos";
   }
   ?>

Answer 1

您是否阅读过文档？ flickr.photos.search

这些方法返回类似的数据，但顶级数组的名称不同（照片与 photoset ）。假设您修改了参数以使用正确的方法并传递适当的参数，那么您需要更改的另一件事就是这一行：

$photos = $rsp_obj["photos"]["photo"];

Answer 2

使用此查询网址：

http://flickr.com/services/rest/?method=flickr.photos.search&api_key=YOUR-KEY&text=YOUR-SEARCH TERM＆amp; per_page = 10＆amp; format = php_serial

Flickr API搜索？

2 个答案: