Question

假设我有两个数组...

import { Component, OnInit } from '@angular/core';
import { CommonserviceService } from './../utilities/services/commonservice.service';
import { FormGroup, FormControl } from '@angular/forms';
@Component({
  selector: 'app-home',
  templateUrl: './home.component.html',
  styleUrls: ['./home.component.css']
})
export class HomeComponent implements OnInit {
  getListData: any;
 dataGroup: FormGroup;
 selectedGroups: string[];

  constructor(private commonserviceService: CommonserviceService) {
   this.dataGroup = new FormGroup({
email: new FormControl(''),
password: new FormControl(''),
list: new FormControl('')
});
this.selectedGroups = [];
 }

  ngOnInit() {


  }

onCheckChange(event) {
  if (event.target.checked) {
 this.selectedGroups.push(event.target.value);
} else {
 const index = this.selectedGroups.findIndex(item => item === event.target.value);
 if (index !== -1) {
  this.selectedGroups.splice(index, 1);
}
}
}

   getFormData(value){
      value['groups'] = this.selectedGroups;
      console.log(value);
  }


}

我知道我可以使用嵌套的for循环将'age'对象设置为array2中的值。但是，使用诸如find或map之类的javascript方法还有另一种方法吗？因此理想的结果将是...

df1['C']=df2.C.reindex(df1.index.get_level_values(0)).values
df1
                A         B         C
bar one -0.007969  0.754405 -0.137703
    two -0.690867 -0.223325 -0.137703
baz one  1.490032 -2.207812 -1.145512
    two  1.428660 -0.982451 -1.145512
foo one -1.203488 -2.190912       NaN
    two -0.791889 -0.199983       NaN

还有什么是array2 ...

array1 = [{'age':'', 'name':'John'}, {'age':'', 'name':'Mark'}, {'age':'', 'name':'Curtis'}]


array2 = ['23','25','29']

即使对象名称不同，我也可以做同样的事情吗？谢谢。

Answer 1

使用Array.map()，并使用索引（age）从第一个数组中提取i，并使用对象解构进行合并：

const array1 = [{'age':'', 'name':'John'}, {'age':'', 'name':'Mark'}, {'age':'', 'name':'Curtis'}]
const array2 = ['23','25','29']

const result = array1.map((o, i) => ({ ...o, age: array2[i] }))

console.log(result)

处理array2的第二版是类似的，使用索引并取值：

const array1 = [{'age':'', 'name':'John'}, {'age':'', 'name':'Mark'}, {'age':'', 'name':'Curtis'}]
array2 = [{'value':'23'},{'value':'25'},{'value':'29'}]

const result = array1.map((o, i) => ({ ...o, age: array2[i].value }))

console.log(result)

打字稿：如何从另一个数组中设置对象数组中的值

1 个答案: