在多维数组PHP中搜索所有键

时间:2011-04-29 18:07:52

标签: php arrays search multidimensional-array

我想在多维数组中搜索特定字符串的所有键。我只需要解决它的现状,仅此而已。我想知道任何数组中是否存在访问者的IP。

我是否可以使用php函数或方法来执行此操作,我尝试过的每个函数或方法都会返回false。 (in_array,array_search,array_filter)

我希望避免循环遍历每个键和一组值。

示例数组

Array
(
    [21] => Array
        (
            [click_id] => 21
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:56:57
            [url_id] => 11
        )

    [22] => Array
        (
            [click_id] => 22
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:57:05
            [url_id] => 12
        )

    [23] => Array
        (
            [click_id] => 23
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 18:42:42
            [url_id] => 10
        )
)

由于

3 个答案:

答案 0 :(得分:1)

我可以想象一种你不必循环的方式(至少你自己):

$term = preg_quote('109.148.183.1', '~'); // lets make sure it's safe
$result = array_map('unserialize', preg_filter('~' . $term . '~', '$0', array_map('serialize', $data)));

echo '<pre>';
print_r($result);
echo '</pre>';

使用您的示例数据:

$data = array
(
    21 => array
    (
        'click_id' => 21,
        'ip_addr' => '109.148.183.1',
        'dtime' => '2011-04-28 17:56:57',
        'url_id' => 11,
    ),

    22 => array
    (
        'click_id' => 22,
        'ip_addr' => '109.148.183.1',
        'dtime' => '2011-04-28 17:57:05',
        'url_id' => 12,
    ),

    23 => array
    (
        'click_id' => 23,
        'ip_addr' => '109.148.183.1',
        'dtime' => '2011-04-28 18:42:42',
        'url_id' => 10,
    ),
);

它正确返回值21的键(2223109.148.183.1):

Array
(
    [21] => Array
        (
            [click_id] => 21
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:56:57
            [url_id] => 11
        )

    [22] => Array
        (
            [click_id] => 22
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:57:05
            [url_id] => 12
        )

    [23] => Array
        (
            [click_id] => 23
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 18:42:42
            [url_id] => 10
        )
)

由于这是一个正则表达式,我们可以进行更强大的搜索,例如搜索奇数秒的所有2011-04-28日期:

$term = '2011-04-28 [0-9]{2}:[0-9]{2}:[0-9][13579]';
$result = array_map('unserialize', preg_filter('~' . $term . '~', '$0', array_map('serialize', $data)));

echo '<pre>';
print_r($result);
echo '</pre>';

输出:

Array
(
    [21] => Array
        (
            [click_id] => 21
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:56:57
            [url_id] => 11
        )

    [22] => Array
        (
            [click_id] => 22
            [ip_addr] => 109.148.183.1
            [dtime] => 2011-04-28 17:57:05
            [url_id] => 12
        )
)

答案 1 :(得分:0)

永远无法避免循环: - )

function search($array, $searchString){
   foreach($array as $key=>$val){
        if(in_array($searchString, $val)) return true;
   }
   return false;
}

//use it like so:
if(search($array, '109.148.183.1')){/*do something*/}

答案 2 :(得分:0)

$matching_keys = array();

function search ($item, $key) {
  global $matching_keys();
  // do your testing here, stuff matches in $matching_keys, or however you wanna do it
}
array_walk_recursive($array, 'search');

或者,您可以编写自己的递归函数并避免使用全局函数。这只是最直接的方式。