我有一个带有日期列的表格,如下所示:
2011-04-28, 2011-04-29 ...
day count name surname
2011-04-28 8 titi tutu
2011-04-28 12 tutu toto
2011-04-27 2 tutu toto
2011-03-12 10 tutu toto
我可以获得截然不同的一天,但不仅仅是月份和年份。
select distinct(day) from Table where day between "2011-03-01" and "2011-04-28";
我只想要明确的月份和年份。
你能帮助我吗?
由于
答案 0 :(得分:2)
select DISTINCT EXTRACT(YEAR_MONTH FROM `day`) as yearmonth
from Table
where day between '2011-03-01' and '2011-04-28';
答案 1 :(得分:1)
DISTINCT可能只适用于mysql中的整行。因此,您需要extract从日期开始所需的内容。
select distinct(EXTRACT YEAR_MONTH FROM `day`) from Table
where day between "2011-03-01" and "2011-04-28";