我试图从仅IFF的字符串返回匹配项，而另一个模式在Oracle中首先使用from string import Template
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
MY_ADDRESS = 'myemail'
def get_contacts(filename):
names = []
emails = []
with open(filename, mode='r', encoding='utf-8') as contacts_file:
for a_contact in contacts_file:
names.append(a_contact.split()[0])
emails.append(a_contact.split()[1])
return names, emails
def read_template(filename):
with open(filename, 'r', encoding='utf-8') as template_file:
template_file_content = template_file.read()
return Template(template_file_content)
def main():
names, emails = get_contacts('mycontacts.txt') # read contacts
message_template = read_template('message.txt')
# set up the SMTP server
s = smtplib.SMTP(host='my.smpt.server')
# s.starttls()
#s.login(MY_ADDRESS, PASSWORD)
# For each contact, send the email:
for name, email in zip(names, emails):
msg = MIMEMultipart() # create a message
# add in the actual person name to the message template
message = message_template.substitute(PERSON_NAME=name.title())
# Prints out the message body for our sake
print(message)
# setup the parameters of the message
msg['From']=MY_ADDRESS
msg['To']=email
msg['Subject']="This is TEST"
# add in the message body
msg.attach(MIMEText(message, 'plain'))
part = MIMEBase('application', "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet")
part.set_payload(open("my_filename.xlsx", "rb").read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="my_filename.xlsx"')
msg.attach(part)
# send the message via the server set up earlier.
s.send_message(msg)
del msg
# Terminate the SMTP session and close the connection
s.quit()
if __name__ == '__main__':
main()
和RegEx_Like进行匹配，但是结果却不尽相同。
下面是我拥有的数据以及我要从中返回的数据的示例：
+-----------------------------+---------+ | Data | Goal | +-----------------------------+---------+ | 201301-P706466 JFK CLASSICS | P706466 | | 201301-706466 WRI CLASSICS | 706466 | | 201301 706466 JFK CLASSICS | 706466 | | 201301 P706466 WRI CLASSICS | 706466 | | 201910-MLB-CVG4 | NULL | | 201209-JFK CLASSICS | NULL | | 201203-WRI CLASSICS | NULL | | 201209 JFK CLASSICS | NULL | | 201203 WRI CLASSICS | NULL | +-----------------------------+---------+
查询：
RegExp_Substr我尝试了this的不同变体，但是在regex101上，但是正如您将在导航到链接后所看到的那样，它比我所需要的要匹配得多。
我想我可能一起走错路了，这就是为什么我在这里。话虽如此，哪种模式最适合我的情况，并且最有效？