Question

经过研究，我如何从StackOverflow获得此代码并运作良好

对于此视频ID = 6chhghoMGVQ，但是当我将此T系列VFTSW817JlI的视频ID放入时，出现错误消息Status => UNPLAYABLE

这是此视频ID = 6chhghoMGVQ的有效代码链接

signature issue when I want to get a direct URL from YouTube via PHP

最后，我在此链接https://www.youtube.com/get_video_info?sts=18177&video_id=$v&asv=3&el=detailpage&hl=en_US&eurl=https://youtube.googleapis.com/v/$v上做了一些更改

代替此链接https://www.youtube.com/get_video_info?video_id=$v 更改链接I Got Status For Video UNPLAYABLE TO OK

之后

但是现在我无法获取URL，因为如果我更改了URL名称，cipher就是

"url" => $array["streamingData"]["formats"][$a]["url"], [“ url”]加密我得到URL但不能播放URL得到错误消息403

我有旧的密码签名解码器代码，但无法正常工作

这是我尝试过的代码。

    <?php
    function YT_IN_DX($url){
        $cookie_file_path = "cookies.txt";
        $agent            = "Mozilla/5.0 (Windows NT 10.0; WOW64; rv:43.0) Gecko/20100101 Firefox/46.0";
        $ch               = curl_init();
        $headers[]        = "Connection: Keep-Alive";
        curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
        curl_setopt($ch, CURLOPT_HEADER, 1);
        curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
        curl_setopt($ch, CURLOPT_USERAGENT, $agent);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
        curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie_file_path);
        curl_setopt($ch, CURLOPT_COOKIEJAR, $cookie_file_path);
        curl_setopt($ch, CURLOPT_URL, $url);
        $res = curl_exec($ch);
        curl_close($ch);
        return $res;
    }

    function YT_V_INFO($v){
        $url         = "https://www.youtube.com/get_video_info?sts=18177&video_id=$v&asv=3&el=detailpage&hl=en_US&eurl=https://youtube.googleapis.com/v/$v";
        $html        = urldecode(YT_IN_DX($url));
        $video_links = Explode_Content('playabilityStatus', 'adSafetyReason', $html);
        $json        = str_replace("\u0026", "&", $video_links);
        $json        = '{"playabilityStatus' . $json . 'adSafetyReason":{"isEmbed":true}}';
        $array       = json_decode($json, true);

        if (isset($array["playabilityStatus"]["status"]) && $array["playabilityStatus"]["status"] == "UNPLAYABLE") {
            $data = array("error" => $array["playabilityStatus"]["status"]);
        }else{
            $formats = $array["streamingData"]["formats"];
            for ($a = 0; $a <= (count($formats) - 1); $a++){
                $data[] = array(
                    "url" => $array["streamingData"]["formats"][$a]["url"],
                    "mimeType" => $array["streamingData"]["formats"][$a]["mimeType"],
                    "quality" => $array["streamingData"]["formats"][$a]["quality"],
                    "qualityLabel" => $array["streamingData"]["formats"][$a]["qualityLabel"],
                    "width" => $array["streamingData"]["formats"][$a]["width"],
                    "height" => $array["streamingData"]["formats"][$a]["height"],
                    "audioQuality" => $array["streamingData"]["formats"][$a]["audioQuality"],
                    "approxDurationMs" => $array["streamingData"]["formats"][0]["approxDurationMs"]
                );
            }
        }
        return $data;
    }
    function Explode_Content($first, $last, $string)
    {
        $exp = explode($first, $string);
        $exp = explode($last, $exp[1]);
        return $exp[0];
    }

    // $videoinfo=YT_V_INFO("sJsoyuQAepQ");

    $videoinfo = YT_V_INFO("VFTSW817JlI");
    echo '<pre>';
    print_r($videoinfo);

    ?>

这是签名解码器

function decrypt_sig($s,$algo) {

    $method = explode(" ",$algo);

    foreach($method as $m)
    {
        if($m == 'r')
            $s = strrev($s);
        else if( substr($m,0,1) == 's')
            $s = substr($s, (int) substr($m,1) );
        else if( substr($m,0,1) == 'w')
            $s = swap($s, (int) substr($m,1));
    }
    return $s;
}
function swap($a, $b) {
    $c = $a[0];
    $a[0] = $a[$b % strlen($a)];
    $a[$b] = $c;
    return $a;
}

算法键：{"sts":"18177","algo":"r w22 s3 w42 r"}

密码Youtube视频数据获取问题PHP

0 个答案: