Question

我试图做一个简单的计算，但是一旦用户输入了重量，它就不会打印出剩余的剩余重量。附带错误代码

--'str'和'int'的不受支持的操作数类型

这是我的代码。有什么我想念的吗？

def Massallowance():
    person = input("Crew or Specialist? ")
    if person== 'Crew':
        definedMass = 100
        weight = input("Please enter weight: ")
        print("Allowance" + weight-definedMass)
    elif person== 'Specialist':
        definedMass = 150
        weight = input("Please enter weight: ")
        print("Allowance" + weight-definedMass)

Answer 1

input()为您提供了字符串，您无法从数字中减去字符串-这没有任何意义。您应该使用int或float

将输入字符串转换为数字

def Massallowance():
        person = input("Crew or Specialist? ")
        if person== 'Crew':
            definedMass = 100
            weight = int(input("Please enter weight: "))
            print("Allowance" + weight-definedMass)
        elif person== 'Specialist':
           definedMass = 150
           weight = int(input("Please enter weight: "))
           print("Allowance" + weight-definedMass)

Answer 2

“输入”方法将“字符串”作为输入。因此，无论何时用户输入数字，它都会直接转换为“字符串”。由于无法用整数替换字符串，因此会出现错误。这应该是一个简单的解决方法：

def Massallowance():
        person = input("Crew or Specialist? ")
        if person== 'Crew':
            definedMass = 100
            weight = int(input("Please enter weight: "))
            print("Allowance" + weight-definedMass)
        elif person== 'Specialist':
           definedMass = 150
           weight = int(input("Please enter weight: "))
           print("Allowance" + weight-definedMass)

Answer 3

您正在尝试在minus和str之间进行int操作首先将输入字符串转换为int，然后执行操作。

weight = int(input("Please enter weight: "))

更新后的代码就像

def Massallowance():
    person = input("Crew or Specialist? ")
    if person== 'Crew':
        definedMass = 100
        weight = int(input("Please enter weight: "))
        print("Allowance" + weight-definedMass)
    elif person== 'Specialist':
        definedMass = 150
        weight = int(input("Please enter weight: "))
        print("Allowance" + weight-definedMass)

错误！不支持减号吗？从输入重量

3 个答案: