Question

这是我的数据

每次用户输入代码时，它都应该是唯一的；如果存在值，它应该显示为错误，例如存在分支代码。

 branches: [
          {
            code: "test",
            name: "test",
            email: "test",
            website: "test.com",
            phone: "test",
            address: {
              street: "test",
              city: "test",
              township: "test",
              state: "test",
              zip_code: "test",
              country: "test",
            },
            google_maps_url: "test.com",
          },
        ],

这是我的代码，现在我没有发布完整的数据，忽略了company_details，这更复杂了，在这里我无法显示特定索引字段的错误。索引作为v-on模糊功能的参数。

 for(var i=0; i < this.company_details.branches.length; i++){
        if( this.company_details.branches[i].code == this.company_details.branches[index].code){
          count +=1;
        }

        if (count==2){
          this.BranchCodeArray[index].exists = true;
        }
        else{
          this.BranchCodeArray[index].exists = false;
        }

Answer 1

据我了解，您想输入一些信息，看看输入是否存在于代码字段中？

您可以使用过滤器获取输入匹配的项数，如果结果数组的长度> 0，则输入不是唯一的。

const branches= [
  {
    code: 'test',
    name: 'test',
    email: 'test',
    website: 'test.com',
    phone: 'test',
    address: {
      street: 'test',
      city: 'test',
      township: 'test',
      state: 'test',
      zip_code: 'test',
      country: 'test'
    },
    google_maps_url: 'test.com'
  }
];

const doesExist = 'code';
const doesNotExist = 'does not exist'

const exists = !!branches.filter((branch) => branch.code === doesExist).length

const notExists = !!branches.filter((branch) => branch.code === doesNotExist).length

您还可以映射数据以生成平面代码。然后，您可以查看codes数组是否包含您的输入数据。

const branches= [
  {
    code: 'test',
    name: 'test',
    email: 'test',
    website: 'test.com',
    phone: 'test',
    address: {
      street: 'test',
      city: 'test',
      township: 'test',
      state: 'test',
      zip_code: 'test',
      country: 'test'
    },
    google_maps_url: 'test.com'
  }
];

const doesExist = 'code';
const doesNotExist = 'does not exist'

const codes = branches.map((branch) => branch.code);

if(codes.includes(doesExist)){
  // Your error logic
}

codes.includes(doesNotExist)

如何验证给定输入是否存在于json数组中？

1 个答案: