Question

我的查询正在使用LISTAGG，并且显示错误00937。00000-“不是单组分组函数” 我经历了很多类似于此错误的stackoverflow问题，这些答案正在使用一些子查询来解决问题。我不想在此查询中编写子查询

SELECT DISTINCT AMD.UNID AS APPLICATION_REF_ID, 
LISTAGG(LOC.PLT,',') WITHIN GROUP (ORDER BY LOC.PLT ) AS MYLOC  
FROM TAB1 AMD
LEFT JOIN TAB2 PER
ON NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID
LEFT JOIN TAB3 LOC
ON NVL(AMD.PERMITNEWID, AMD.PERMITID) = LOC.PERMITID
WHERE NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID

Answer 1

尝试分组依据：

SELECT amd.unid AS application_ref_id,
       LISTAGG (loc.plt, ',') WITHIN GROUP (ORDER BY loc.plt) AS myloc
  FROM tab1 amd
       LEFT JOIN tab2 per ON NVL (amd.permitnewid, amd.permitid) = per.unid
       LEFT JOIN tab3 loc
           ON NVL (amd.permitnewid, amd.permitid) = loc.permitid
 WHERE NVL (amd.permitnewid, amd.permitid) = per.unid
GROUP BY amd.unid

Answer 2

您缺少group by，如果您要按distinct()分组，则不需要UNID

SELECT AMD.UNID AS APPLICATION_REF_ID, 
LISTAGG(LOC.PLT,',') WITHIN GROUP (ORDER BY LOC.PLT ) AS MYLOC  
FROM TAB1 AMD
LEFT JOIN TAB2 PER
ON NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID
LEFT JOIN TAB3 LOC
ON NVL(AMD.PERMITNEWID, AMD.PERMITID) = LOC.PERMITID
WHERE NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID
GROUP BY AMD.UNID

使用LISTAGG

2 个答案: