如何使用bash注释掉任意范围的行？

Question

说我有以下file.txt

some line 

{
  hey it's me, another line
}

# START FOO
These lines
need to be commented
out
# END FOO

Some other line

如何注释掉# START FOO中标记# END FOO和bash之间的所有行？一口气可以做到吗？

Answer 1

尝试一下：

sed '/START FOO/,/END FOO/s/^/#/' file.txt