Question

我在db中有一个日期字段。

我想要周六周日和周一之间的所有数据。
在这些数据中，我只想要一条记录，其日期是下一个日期

希望我能清楚自己

Answer 1

SELECT DAYOFWEEK(date) as wd FROM table WHERE wd > 1 AND wd < 6 AND date >= CURRENT_TIMESTAMP() ORDER BY date ASC LIMIT 1;

Answer 2

$from = strtotime('saturday');
$to   = strtotime('tueseday') - 1; // whole monday

mysql_query('SELECT * FROM table WHERE date >= ' . $from . ' AND date <= ' . $to . ' ORDER BY date LIMIT 1');

Answer 3

这将从数据库中返回您需要的数据：

//once you've connected to the DB
$db_query= "SELECT * FROM table 
            WHERE DATEDIFF(CURDATE(), date)>0 
            AND (DAYOFTHEWEEK(date)<3 OR DAYOFTHEWEEK(date)==7)
            ORDER BY date
            LIMIT 0,1";//limits it to one (date) result
$result=mysql_query($db_query);
if(!$result){ die('ERROR: Query failed.'); }

这将在屏幕上打印结果行：

while($ROW=mysql_fetch_assoc($result))
{
    echo "<p>date: {$ROW['date']}</p>";
    //do the same for all the fields you want like so:
    echo "<p>other field: {$ROW['other field']}</p>";
}

mysql_free_result($result);

Answer 4

SELECT * FROM table WHERE DATEDIFF（CURDATE（），date）＆gt; 0 AND（DAYOFWEEK（date）in（1,2,7）ORDER BY date LIMIT 0,1

Mysql日期问题

4 个答案: