Question

尝试透视数据并添加计算列无济于事。

我已经尝试了下面的封闭代码，但无法确切获得我想要的。

我的表格由三列组成

TABLE_NAME，REPORT_DATE，COUNT_ROWS

对于最后两个[REPORT_DATE]，我试图显示每个[TABLE_NAME]的[COUNT_ROWS]

我想念什么？另外，我将如何添加一列以减去数据透视图中两个日期之间的值？

DECLARE @cols  AS NVARCHAR(MAX)='';
DECLARE @query AS NVARCHAR(MAX)='';

SELECT @cols = @cols + QUOTENAME(REPORT_DATE) + ',' FROM (select DISTINCT TOP 2 REPORT_DATE from account_report order by  REPORT_DATE desc) as tmp
select @cols = substring(@cols, 0, len(@cols)) --trim "," at end

set @query = 
'SELECT * from 
(select  [TABLE_NAME], [COUNT_ROWS] from account_report
) src
pivot 
(sum([COUNT_ROWS]) for [TABLE_NAME] in (' + @cols + ')
) piv'

execute(@query)

我从脚本中获得的是两个[REPORT_DATE]的两列结果，其中1行显示空值（尽管我的数据中确实包含行）

Answer 1

我敢打赌，您正在尝试从查询中获取以下信息：

SELECT * from 
(select  [TABLE_NAME], [COUNT_ROWS], [REPORT_DATE] from account_report
) src
pivot 
(sum([COUNT_ROWS]) for [REPORT_DATE] in (' + @cols + ')
) piv

相反，如果您确实希望报表名称按列推出，则需要调整@cols变量。

SELECT @cols = @cols + QUOTENAME(TABLE_NAME) + ',' FROM (select DISTINCT TOP 2 TABLE_NAME ,REPORT_DATE from account_report order by  REPORT_DATE desc) as tmp
select @cols = substring(@cols, 0, len(@cols)) --trim "," at end

set @query = 
'SELECT * from 
(select  [REPORT_DATE], [TABLE_NAME], [COUNT_ROWS] from account_report 
) src
pivot 
(sum([COUNT_ROWS]) for [TABLE_NAME] in (' + @cols + ')
) piv'

execute(@query)

枢轴问题（我缺少什么）？

1 个答案: